Only binomials have conjugates. 6√2 is not a binomial, so it has no conjugate.
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a radical b or -a - radical b
6 radical 2
4 radical 6
The conjugate of 6 + i is 6 - i.
its the same as itself. since there is no radical part
a radical b or -a - radical b
12 radical 2 you multiply 6 and 2 :)
2
6 radical 2
4 radical 6
To eliminate the radical in the denominator.
The conjugate of 6 + i is 6 - i.
its the same as itself. since there is no radical part
First, note that radical 4 is 2. So 3xradical 4 is just 6, Now we have 6+2 radical 3. You can't do much with this except factor out a 2 if you want 2(3+Radical 3)
1 over 2 times radical 6
3root(6)+5root(2) you really answered it yourself!
3^3*radical(128) = 3^3*radical(2^7) = 3^3*radical(2^6*2) =3^3*2^3*radical(2) = 216*radical(2).