It is -13.
x2/172 - y2/b2 = 1 for some constant b.
x2 + x2 + x2 = (1 + 1 + 1)x2 = 3x2
The two binomials can be written as (x - a)(x + a), for any constant a. Proof: Expand using FOIL: (x - a)(x + a) = x2 + xa - xa - a2 Group: (x - a)(x + a) = x2 - a2 x2 - a2 is a difference of squares. Thus, the product of (x - a) and (x + a) is a difference of squares.
If x has the power 2 then you want the integral of x2, I think. When you integrate this you get : x3/3 , plus a constant.
It is -13.
The anti-derivative of X2 plus X is the same as the anti-derivative of X2 plus the anti-derivative of X. The anti derivative of X2 is X3/3 plus an integration constant C1 The anti derivative of X is X2/2 plus an integration constant C2 So the anti-derivative of X2+X is (X3/3)+(X2/2)+C1+C2 The constants can be combined and the fraction can combined by using a common denominator leaving (2X3/6)+(3X2/6)+C X2/6 can be factored out leaving (X2/6)(2X+3)+C Hope that helps
x2-2x+C, where C is some arbitrary constant.
Choice A. Polynomial is a trinomial with a constant term 7.
The binomial usually has an x2 term and an x term, so we complete the square by adding a constant term. If the coefficient of x2 is not 1, we divide the binomial by that coefficient first (we can multiply the trinomial by it later). Then we divide the coefficient of x by 2 and square that. That is the constant that we need to add to get the perfect square trinomial. Then just multiply that trinomial by the original coefficient of x2.
x2/172 - y2/b2 = 1 for some constant b.
x2 + x2 + x2 = (1 + 1 + 1)x2 = 3x2
The GCF is x2.
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x2 + x2 = 2x2
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