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How do you find the exact value of cos 5pi over 6?
To find the exact value of (\cos\left(\frac{5\pi}{6}\right)), first note that (\frac{5\pi}{6}) is located in the second quadrant, where cosine values are negative. The reference angle is (\pi - \frac{5\pi}{6} = \frac{\pi}{6}). The cosine of (\frac{\pi}{6}) is (\frac{\sqrt{3}}{2}), so (\cos\left(\frac{5\pi}{6}\right) = -\frac{\sqrt{3}}{2}). Thus, the exact value is (-\frac{\sqrt{3}}{2}).
What is the measure of an angle whose cosine 0.5?
The measure of an angle whose cosine is 0.5 is 60 degrees (or (\frac{\pi}{3}) radians) in the first quadrant. Additionally, in the context of the unit circle, the angle can also be 300 degrees (or (\frac{5\pi}{3}) radians) in the fourth quadrant.
What is the tangent of pi over 5?
Tan(Pi/5) = √(5-2*√(5)) ~= 0.7265
What quadrant would pi over 5 be in?
Pi / 5 would be in Quadrant I.
What quadrant would 7 pi over 5 be in?
7*pi/5 = 1.4*pi pi < 1.4*pi < 1.5*pi and so the angle is in the third quadrant.
How do you find the exact value of cos 5pi over 6?
To find the exact value of (\cos\left(\frac{5\pi}{6}\right)), first note that (\frac{5\pi}{6}) is located in the second quadrant, where cosine values are negative. The reference angle is (\pi - \frac{5\pi}{6} = \frac{\pi}{6}). The cosine of (\frac{\pi}{6}) is (\frac{\sqrt{3}}{2}), so (\cos\left(\frac{5\pi}{6}\right) = -\frac{\sqrt{3}}{2}). Thus, the exact value is (-\frac{\sqrt{3}}{2}).
What is the period of the sinusoid given by y equals -3 cos 2 pi over 5x?
The period of a sinusoidal function is determined by the coefficient of (x) in the cosine or sine function. For the function (y = -3 \cos\left(\frac{2\pi}{5}x\right)), the coefficient of (x) is (\frac{2\pi}{5}). The period (P) is given by the formula (P = \frac{2\pi}{\text{coefficient of } x}). Therefore, the period of this sinusoid is (P = \frac{2\pi}{\frac{2\pi}{5}} = 5).
What is the measure of an angle whose cosine 0.5?
The measure of an angle whose cosine is 0.5 is 60 degrees (or (\frac{\pi}{3}) radians) in the first quadrant. Additionally, in the context of the unit circle, the angle can also be 300 degrees (or (\frac{5\pi}{3}) radians) in the fourth quadrant.
What is the tangent of pi over 5?
Tan(Pi/5) = √(5-2*√(5)) ~= 0.7265
What quadrant would pi over 5 be in?
Pi / 5 would be in Quadrant I.
What quadrant would you find pi over 5 in?
Pi / 5 would be in Quadrant I.
What quadrant would 7 pi over 5 be in?
7*pi/5 = 1.4*pi pi < 1.4*pi < 1.5*pi and so the angle is in the third quadrant.
What is the volume of paint in a can that has a diameter of 10 inches and a height of 12 inches?
pi*r squared*h pi*5 squared*12 pi*25*12 942!
If Cosine x degrees equals 5 over 7 what is x?
Approx 44.4 degrees.
What is the radius of a cylinder with a radius of 1cm and a height of 5cm?
The radius is in the question 1cm the volume is pi * R^2 * H = pi *1 ^ 1 * 5 = 5 * pi surface area pi * 2 * R * 5 + 2 * ( pi * r ^2) = 10 * pi + 2 * pi = 12 * pi
What is pi times 24 over 5?
15.072
What is 5 over 12 plus 5 over 12?
The sum of 5/12 and 5/12 is 5/6
