Tan(Pi/5) = √(5-2*√(5)) ~= 0.7265
Pi / 5 would be in Quadrant I.
7*pi/5 = 1.4*pi pi < 1.4*pi < 1.5*pi and so the angle is in the third quadrant.
pi*r squared*h pi*5 squared*12 pi*25*12 942!
Approx 44.4 degrees.
Tan(Pi/5) = √(5-2*√(5)) ~= 0.7265
Pi / 5 would be in Quadrant I.
Pi / 5 would be in Quadrant I.
7*pi/5 = 1.4*pi pi < 1.4*pi < 1.5*pi and so the angle is in the third quadrant.
pi*r squared*h pi*5 squared*12 pi*25*12 942!
Approx 44.4 degrees.
The radius is in the question 1cm the volume is pi * R^2 * H = pi *1 ^ 1 * 5 = 5 * pi surface area pi * 2 * R * 5 + 2 * ( pi * r ^2) = 10 * pi + 2 * pi = 12 * pi
15.072
The sum of 5/12 and 5/12 is 5/6
5 over 12 = 5/12 in fraction
5 over 12 (5/12) is the same as 5 divided by 12: 5 ÷ 12 = 0.4167
12/5 ÷ 12/9 = 12/5 x 9/12 = 9/5 = 14/5