a3 - 2a2 + 4a - 8 = a2(a - 2) + 4(a - 2) = (a - 2)(a2 + 4)
First you can factor a^2 from the first two terms and 4 from the last two terms. (a^2)(a-2)+4(a-2) You can see that they both have (a-2) as a factor. So it is (a^2+4)(a-2)
A polynomial function of a variable, x, is a function whose terms consist of constant coefficients and non-negative integer powers of x. The general form is p(x) = a0 + a1*x + a2*x^2 + a3*x^3 + ... + an*x^n where a0, a1, ... , an are constants.
That is a very simple equation if A3-2 is equal to A'q*3 then A3-2 is also A3-22.
0
a3 - 2a2 + 4a - 8 = a2(a - 2) + 4(a - 2) = (a - 2)(a2 + 4)
(a - 2)(a^2 + 4)
a3-4a = a(a2-4) when factored
First you can factor a^2 from the first two terms and 4 from the last two terms. (a^2)(a-2)+4(a-2) You can see that they both have (a-2) as a factor. So it is (a^2+4)(a-2)
4a4 + 11a3 - 47a3 - 4a + 5 =4a4 - 36a3 - 4a + 5 =4a (a3 - 9a2 - 1) + 5
(a + 4)(a^2 - 4a + 16)
2a3 - 128 = 2*(a3 - 64) = 2*(a -4)*(a2 + 4a + 16)
4a7 / 3a3 = ( 4/3 ) x ( a7/a3 ) = 4a4 / 3
A polynomial function of a variable, x, is a function whose terms consist of constant coefficients and non-negative integer powers of x. The general form is p(x) = a0 + a1*x + a2*x^2 + a3*x^3 + ... + an*x^n where a0, a1, ... , an are constants.
(a+b)2a2+b2+2ab(a-b)2=a2+b2-2ab(a+b)2=(a-b)2+4ab(a-b)2=(a+b)2-4aba2-b2=(a+b)(a-b)(a+b+c)2=(a+b+c+2ab+2bc+2cz)(a+b)3=a3+b3+3ab(a+b)(a-b)3=a3-b3-3ab(a-b)a3+b3=(a-b)(a2-ab+b2)a3-b3=(a+b)(a2+ab+b2)a3+b3+c3-3abc=(a+b+c)(a2+b2+c2-ab-bc-ca)(x+a)(x+b)=x2+x(a+b)+ab ==3a+10b-b+2a=5a+9by=mx+b is another one
There following two options should work:=sum(A1:A3) or=A1+A2+A3
A3+b3