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If you mean: y =(lnx)3

then:

dy/dx = [3(lnx)2]/x

ddy/dx = [(6lnx / x) - 3(lnx)2] / x2

If you mean: y = ln(x3)

Then:

dy/dx = 3x2/x3 = 3/x = 3x-1

ddy/dx = -3x-2 = -3/x2

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