negative cotangent -- dcot(x)/dx=-csc^2(x)
No. The inverse of the secant is called the arc-secant. The relation between the secant and the cosecant is similar to the relation between the sine and the cosine - they are somehow related, but they are not inverse functions. The secant is the reciprocal of the cosine (sec x = 1 / cos x). The cosecant is the reciprocal of the sine (cos x = 1 / sin x).
Derivative of 1/x 1/x = x-1 Take the derivative (-1)x(-1-1) = -x-2 = 1/x2
1/cos(x)=sec(x). sec is short for secant.
The derivative of sin(x) is cos(x).
negative cotangent -- dcot(x)/dx=-csc^2(x)
Given y = tan x: dy/dx = sec^2 x(secant of x squared)
According to Wolfram Alpha, input:integral csc x it is -log[cot(x) + csc(x)] + constant You can verify this by taking the derivative of the purported integral.
the derivative of tangent dy/dx [ tan(u) ]= [sec^(2)u]u' this means that the derivative of tangent of u is secant squared u times the derivative of u.
Secant is a trignometric function. In a right triangle, the secant of an angle is the hypotenuse over the adjacent side. It is also the inverse of cosine. For example secant(x) = 1/cos(x)
d/dx sec(2x) = 2sec(2x)tan(2x)
No. The inverse of the secant is called the arc-secant. The relation between the secant and the cosecant is similar to the relation between the sine and the cosine - they are somehow related, but they are not inverse functions. The secant is the reciprocal of the cosine (sec x = 1 / cos x). The cosecant is the reciprocal of the sine (cos x = 1 / sin x).
Substitute secant(x)=1/cos(x) into your equation, and you should be able to solve from there.
Sine and cosine are cofunctions, which means that their angles are complementary. Consequently, sin (90° - x) = cos x. Secant is the reciprocal of cosine so that sec x = 1/(cos x). Knowing these properties of trigonometric functions, among others, will really help you in other advance math courses.
The derivative of ln x is 1/x The derivative of 2ln x is 2(1/x) = 2/x
The derivative of cos(x) is negative sin(x). Also, the derivative of sin(x) is cos(x).
The derivative of 3cos(x) is -3sin(x). This can be found using the chain rule, which states that the derivative of a composition of functions is the derivative of the outer function evaluated at the inner function, multiplied by the derivative of the inner function. In this case, the derivative of cos(x) is -sin(x), and when multiplied by the constant 3, we get -3sin(x) as the derivative of 3cos(x).