There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)
In any two-digit multiplication sum, for example, 3 x 2 = 6, the first digit is called the multiplier, the second digit is called a multiplicand, and the third digit, the answer, is the product.
3 digit numbers are lessthan 4 digit numbers
10 because 10 is the first 2 digit number out of all numbers.
There are 900 natural numbers made up of only three digits. This is because there are 9 options for the first digit (1-9), 10 options for the second digit (0-9), and 10 options for the third digit (0-9). Multiplying these options together gives us 9 x 10 x 10 = 900 possible three-digit natural numbers.
The last digit in the product of the first 20 odd natural numbers can be determined by looking at the pattern of the units digit in the multiplication of consecutive odd numbers. The units digit of the product of consecutive odd numbers alternates between 1 and 5. Since there are 10 odd numbers between 1 and 19, and 20 is also an odd number, the last digit in the product of the first 20 odd natural numbers is 5.
It is 0.
To find the last but one digit in the product of the first 75 even natural numbers, we need to consider the units digit of each number. Since we are multiplying even numbers, the product will end in 0. Therefore, the last but one digit (tens digit) will depend on the multiplication of the tens digits of the numbers. The tens digit will be determined by the pattern of the tens digits of the even numbers being multiplied.
Zero.
Oh, dude, you want to know the unit's digits of the product of the first 21 prime numbers? Well, let me casually tell you that the unit's digit of a product depends on the unit's digits of the numbers being multiplied. Since the unit's digit of all prime numbers greater than 5 is either 1, 3, 7, or 9, the product of the first 21 prime numbers will end in a unit's digit that is a result of multiplying these digits together. Cool, right?
Good question. 1+2+3+4+5=155=15 So the product of first five natural numbers is fifteen Natural numbers starts from one So we add first five natural numbers and get the right answer is fifteen
271 of the first 1000 natural numbers contain at least one digit 5. That is 27.1 % of them.
There are only two prime numbers that are consecutive numbers, 2 and 3. Their product is 2 x 3 = 6. The first prime numbers are 2, 3, 5, and 7 and the only two consecutive prime numbers whose product is a single digit are 2 and 3. (The next two consecutive prime numbers, 3 and 5, have a two-digit product.)
In any two-digit multiplication sum, for example, 3 x 2 = 6, the first digit is called the multiplier, the second digit is called a multiplicand, and the third digit, the answer, is the product.
120
The first 3 digit natural number is 100: 100 ÷ 4 = 25 → first 3 digit natural number divisible by 4 is 4 × 25 The last 3 digit natural number is 999: 999 ÷ 4 = 249 r 3 → last 3 digit natural number divisible by 4 is 4 × 249 → number of 3 digit natural numbers divisible by 4 is 249 - 25 + 1 = 225.
3 digit numbers are lessthan 4 digit numbers