If "50 inches" is the perimeter all you can say is that length plus width = 25 inches.
Its length is 18 inches
yes they can the square could have a side of sqrt of 50 inches just multiply that by itself and you have 50sq inches the rectangles could have a length of 5 and a length of 10. multiply them to gether and y ou have 50sq in
An area of 100 square inches can be enclosed in many different regular or irregular outlines. It is easy to measure in a regular figure, such as: - a square measuring 10 inches on each side. (10*10=100) - a rectangle: for instance, 2 by 50 inches, or 4 by 25 inches, or any length and width that totals 100 square inches. - a circle with a radius of 5.64 inches - a triangle. rectangle, parallelogram, trapezoid, circle, ellipse. Each has a formula for relating area to lengths and angles.
Equally.
If it is a rectangle, the the dimension of Area [Distance²] is (Length) x (Width).So if the the length and width do not have units, then just say 'it is 50 units long' then the area is 1250 units²
0.5
It is 2*(50 + 17) = 2*67 = 134 inches.
If "50 inches" is the perimeter all you can say is that length plus width = 25 inches.
Its length is 18 inches
You need two dimensions to calculate the area of a rectangle. Area = length multiplied by width.
If the area is of a rectangle, it is simply the length times the width. If you have a rectangle with sides of 2 and 50 then the area is 100.
yes they can the square could have a side of sqrt of 50 inches just multiply that by itself and you have 50sq inches the rectangles could have a length of 5 and a length of 10. multiply them to gether and y ou have 50sq in
Width of rectangle: 50/10 = 5 cm
The area of a rectangle is 20 x 50 = 1,000 cm^2
What is the area of a 50x15 rectangle? A = lw = 50x15 = 750
4 x 8 = 32; 5 x 10 = 50 increase of 18/32 which is 56.25%