The answer is (2x^2+3)(4x+1)
2x2+5x+3 = (2x+3)(x+1) when factored
(2x-3)(x-1)
(2x - 1)(x + 3)
8x3 + 4x2 + 6x + 3 = 4x2(2x + 1) + 3(2x + 1) = (2x + 1)(4x2 + 3)
(2x+3)(x+3)
(2x+3)(x+3)
(2x - 3)(2x - 3)
Presumably you mean: -2x2-3x+41 If so then the discriminant is: (-3)2-4*-2*41 = 337 The expession is: i/2+i
(2x+3)(2x+4)
The answer is (2x^2+3)(4x+1)
2x2+5x+3 = (2x+3)(x+1) when factored
(2x-3)(x-1)
(2x - 1)(x + 3)
8x3 + 4x2 + 6x + 3 = 4x2(2x + 1) + 3(2x + 1) = (2x + 1)(4x2 + 3)
(4x + 1)(2x + 3)
Discriminant = (b2-4ac) = (25 - 4x2x3) = 1