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What is the distance between the two points 9 4 and 3 7?
X2=3, X1=9 Y2=7 Y1=4 3-9=-6. -62=36 7-4=3. 32=9 36+9=45 The distance is the square root of 45
What is the distance between points 1 2 and 4 -1?
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
What is the distance between the two points 9 -4 and 3 7?
The distance formula takes the difference between the two x-coordinates (9-3 = 6) and the difference between the two y-coordinates (-4-7 = -11), then squares these two answers (62 = 36 and (-11)2 = 121), then adds them together (36 + 121 = 157), then takes the square root of this final number. Thus the distance between (9, -4) and (3, 7) is sqrt(157), or about 12.53.
What is the distance between the points (7 5) and (4 9)?
To find the distance between the points (7, 5) and (4, 9), you can use the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Plugging in the values, ( d = \sqrt{(4 - 7)^2 + (9 - 5)^2} = \sqrt{(-3)^2 + (4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5 ). Therefore, the distance between the two points is 5 units.
What is the distance between point 4 5 and point 1 1?
The distance is 5. The x distance is 3, the y distance is 4, and the diagonal issqrt(32 + 42) = sqrt (9 + 16) = sqrt 25 = 5
What is the distance between points (9 4) and (3 4) on a coordinate plane?
The distance between points: (9, 4) and (3, 4) is 6
What is the distance between the two points 9 4 and 3 7?
X2=3, X1=9 Y2=7 Y1=4 3-9=-6. -62=36 7-4=3. 32=9 36+9=45 The distance is the square root of 45
What is the distance between the points (-2 -3) and (7 4)?
X2=3, X1=9 Y2=7 Y1=4 3-9=-6. -62=36 7-4=3. 32=9 36+9=45 The distance is the square root of 45
What is the distance between the points (-2 -8) and (7 4)?
X2=3, X1=9 Y2=7 Y1=4 3-9=-6. -62=36 7-4=3. 32=9 36+9=45 The distance is the square root of 45
What is the distance between the points -1 -9 and 4 -2?
Points: (-1, -9) and (4, -2) Distance: (-1-4)2+(-9--2)2 = 74 and the square root of this is the distance which is about 8.602 to 3 decimal places
What is the distance between the points (-5 2) and (4 9)?
Points: (-1, -9) and (4, -2) Distance: (-1-4)2+(-9--2)2 = 74 and the square root of this is the distance which is about 8.602 to 3 decimal places
What is the distance between points 1 2 and 4 -1?
Use Pythagoras to find the distance between two points (x0,.y0) and (x1, y1): distance = √(change_in_x² + change_in_y²) → distance = √((x1 - x0)² + (y1 - y0)²) → distance = √((4 - 1)² + (-1 -2)²) → distance = √(3² + (-2)²) → distance = √(9 + 9) → distance = √18 = 3 √2
What is the distance between (5-9) and (3-9)?
It is: 2
What is the distance between 9 and -3 and 4 and -3?
The easiest way to show these is with a number line. <.....•.....•.....•.....•.....•.....•.....•.....•.....•.....•.....•.....•.....•........> -3 -2 -1 0 +1 +2 +3 +4 +5 +6 +7 +8 +9 From 9 to -3 is 12 units From 4 to -3 is 7 units
What is the distance between the two points 9 -4 and 3 7?
The distance formula takes the difference between the two x-coordinates (9-3 = 6) and the difference between the two y-coordinates (-4-7 = -11), then squares these two answers (62 = 36 and (-11)2 = 121), then adds them together (36 + 121 = 157), then takes the square root of this final number. Thus the distance between (9, -4) and (3, 7) is sqrt(157), or about 12.53.
What is the distance between the numbers -13 and -4?
-9
What is the distance between the points (7 5) and (4 9)?
To find the distance between the points (7, 5) and (4, 9), you can use the distance formula: ( d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} ). Plugging in the values, ( d = \sqrt{(4 - 7)^2 + (9 - 5)^2} = \sqrt{(-3)^2 + (4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5 ). Therefore, the distance between the two points is 5 units.
