Distance2 = (21-9)2 + (16-11)2 = 169 and the square root of this is the distance which is 13 units
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10 units.
15
√((7-3)² + (5 - -2)²) = √(4² + 7²) = √(16+49) = √(65) ≈ 8.062 ■
The distance between two points in a plane can be found using the distance formula: sqrt((x2 - x1)^2 + (y2 - y1)^2). In this case, the distance between the points (-1, 2) and (2, 6) is sqrt((2 - (-1))^2 + (6 - 2)^2) = sqrt(3^2 + 4^2) = sqrt(9 + 16) = sqrt(25) = 5.
Using Pythagoras: distance = √(difference_in_x^2 + difference_in_y^2) = √((6 - 2)^2 + (3 - 4)^2) = √(16 + 1) = √17 ≈ 4.12