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What is the distance between the points (-2 16) and (8 16) in the xy-plane?
10 units.
What is the distance between the numbers 11 and -4?
15
What is the distance between the points 5 7 and -2 3?
√((7-3)² + (5 - -2)²) = √(4² + 7²) = √(16+49) = √(65) ≈ 8.062 ■
What is the distance between the two points -1 2 and 2 6?
The distance between two points in a plane can be found using the distance formula: sqrt((x2 - x1)^2 + (y2 - y1)^2). In this case, the distance between the points (-1, 2) and (2, 6) is sqrt((2 - (-1))^2 + (6 - 2)^2) = sqrt(3^2 + 4^2) = sqrt(9 + 16) = sqrt(25) = 5.
What is the distance between points 2 4 and 6 3?
Using Pythagoras: distance = √(difference_in_x^2 + difference_in_y^2) = √((6 - 2)^2 + (3 - 4)^2) = √(16 + 1) = √17 ≈ 4.12
What is the distance between the points (2116) and (911)?
If you mean points of (21, 16) and (9, 11) then the distance works out as 13
What is the distance between the points 2116 and 911?
If you mean points of (21, 16) and (9, 11) then the distance works out as 13
What is the distance between the points 3 7 and 15 16 on a coordinate plane?
Distance between the points of (3, 7) and (15, 16) is 15 units
What is the distance between the points (-4 5) and (3 16)?
Points: (-4, 5) and (3, 16) Distance: square root of 170 which is about 13
What is the distance between the points (-2 16) and (8 16) in the xy-plane?
10 units.
What is the distance between the numbers 11 and -4?
15
What is the distance between the points 5 7 and -2 3?
√((7-3)² + (5 - -2)²) = √(4² + 7²) = √(16+49) = √(65) ≈ 8.062 ■
What is the distance between the two points -1 2 and 2 6?
The distance between two points in a plane can be found using the distance formula: sqrt((x2 - x1)^2 + (y2 - y1)^2). In this case, the distance between the points (-1, 2) and (2, 6) is sqrt((2 - (-1))^2 + (6 - 2)^2) = sqrt(3^2 + 4^2) = sqrt(9 + 16) = sqrt(25) = 5.
Which is the middle even number between 11 and 21?
It is 16. This is because there are five numbers between 11 and 16, and there are five numbers between 16 and 21 :]
Find the distance between the points -4 15 and 8 -1?
The answer will be the diagonal (hypotenuse) for a horizontal distance x2-x1 (12) and a vertical distance y2-y1 (-16). The square root of the squares is sqrt [122 + (-16)2] = sqrt [144 + 256] = sq rt [400] = 20.
What is the distance between points 2 4 and 6 3?
Using Pythagoras: distance = √(difference_in_x^2 + difference_in_y^2) = √((6 - 2)^2 + (3 - 4)^2) = √(16 + 1) = √17 ≈ 4.12
Find the distance between points -6 1 and 10 -8?
If d is the distance between them, then d2 = (-6 -10)2 + (1 - (-8))2 = (-16)2 + 92 =256 + 81 = 337 so d = sqrt(337) = 18.36
