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What else can I help you with?
What is the cubed root of x2y4?
y times the cube root of x2y
What is the domain of x plus 8 divided by x2-4?
The domain is all real numbers except when the denominator equals zero: x2 - 4 = 0 x2 = 4 x = 2, -2 So the domain is all real numbers except 2 and -2.
What cube of binomials?
(x2 + x2)=
What is the domain of y equals x2?
The domain of y = x2 is [0,+infinity]
What is the cube root of -64?
Suppose x3 = -64 then x3 + 64 = 0So (x + 4)*(x2 - 4x + 16) = 0So x = 4 or x = 2 +/- 2i*sqrt(3) where i is the imaginary square root of -1.-4 * -4 * -4 = -64So cube root of -64 = -4
How come the function y cube root x2 - 1 has the domain -infinity infinity What is the procedure to coming to this solution?
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What is plot graph to hearts and hands?
y = (square root 1- x2) + (cube root x2)
What is the cubed root of x2y4?
y times the cube root of x2y
What is x4 divided by the square root of x4?
1
What is the domain of x plus 8 divided by x2-4?
The domain is all real numbers except when the denominator equals zero: x2 - 4 = 0 x2 = 4 x = 2, -2 So the domain is all real numbers except 2 and -2.
What cube of binomials?
(x2 + x2)=
What is the domain of y equals x2?
The domain of y = x2 is [0,+infinity]
What is the cube root of -64?
Suppose x3 = -64 then x3 + 64 = 0So (x + 4)*(x2 - 4x + 16) = 0So x = 4 or x = 2 +/- 2i*sqrt(3) where i is the imaginary square root of -1.-4 * -4 * -4 = -64So cube root of -64 = -4
What is the square root of x squared plus 1?
square root of (x2 + 1) = no simplification (square root of x2) + 1 = x + 1
Only cube that is one less than a square?
It can be determined by solving the equation: x2-x3 = 1 x2(1-x) = 1 x = - 1/(1-x)1/2 (It can be shown by sketch that the root is negative) By iteration, the root is -0.755 (3 s.f.)
How do you express something in radical form?
Using a radical (square root) bar. I can't get one on the screen, but I'm sure you know what they look like. Example: fractional exponents can be rewritten in radical form: x2/3 means the cube root of (x2) ... write a radical with an index number 3 to show cube root and the quantity x2 is inside the radical. Any fractional exponent can be done the same way. The denominator of the fractional exponent becomes the index of the radical, but the numerator stays as a whole number exponent in the radical.
How do you simplify the cube root of x squared times the square root of x?
Personally I prefer to convert roots to fractional powers for this kind of problem. cube root of x squared is x2/3, and square root of x is x1/2. Adding the exponents, you get x2/3 times x1/2 = x7/6, that is, the sixth root of x to the seventh power - where it doesn't matter whether you take the sixth root first, or raise to the sevents power first. Alternatively, you can convert all roots to sixth roots, and multiply - and of course, get the same result.
