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x ∈ C, x ≠ 0

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16y ago

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How come the function y cube root x2 - 1 has the domain -infinity infinity What is the procedure to coming to this solution?

1


What is plot graph to hearts and hands?

y = (square root 1- x2) + (cube root x2)


What is the cubed root of x2y4?

y times the cube root of x2y


What is x4 divided by the square root of x4?

1


What is the domain of x plus 8 divided by x2-4?

The domain is all real numbers except when the denominator equals zero: x2 - 4 = 0 x2 = 4 x = 2, -2 So the domain is all real numbers except 2 and -2.


What cube of binomials?

(x2 + x2)=


What is the domain of y equals x2?

The domain of y = x2 is [0,+infinity]


What is the cubed root of x to the fifth?

NB Cube Root can be written as the exponent '1/3' Hence [x^(5)]^(1/3) = x^(5/3)


What is the cube root of -64?

Suppose x3 = -64 then x3 + 64 = 0So (x + 4)*(x2 - 4x + 16) = 0So x = 4 or x = 2 +/- 2i*sqrt(3) where i is the imaginary square root of -1.-4 * -4 * -4 = -64So cube root of -64 = -4


Only cube that is one less than a square?

It can be determined by solving the equation: x2-x3 = 1 x2(1-x) = 1 x = - 1/(1-x)1/2 (It can be shown by sketch that the root is negative) By iteration, the root is -0.755 (3 s.f.)


How do you express something in radical form?

Using a radical (square root) bar. I can't get one on the screen, but I'm sure you know what they look like. Example: fractional exponents can be rewritten in radical form: x2/3 means the cube root of (x2) ... write a radical with an index number 3 to show cube root and the quantity x2 is inside the radical. Any fractional exponent can be done the same way. The denominator of the fractional exponent becomes the index of the radical, but the numerator stays as a whole number exponent in the radical.


What is the square root of x squared plus 1?

square root of (x2 + 1) = no simplification (square root of x2) + 1 = x + 1