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How would you solve the integral of 1 plus tan2x plus tan squared 2x?
Integral of 1 is x Integral of tan(2x) = Integral of [sin(2x)/cos(2x)] =-ln (cos(2x)) /2 Integral of tan^2 (2x) = Integral of sec^2(2x)-1 = tan(2x)/2 - x Combining all, Integral of 1 plus tan(2x) plus tan squared 2x is x-ln(cos(2x))/2 +tan(2x)/2 - x + C = -ln (cos(2x))/2 + tan(2x)/2 + C
Whai is the solution to Ln 2x plus 9 equals ln 5x?
That all depends.Is it:ln (2x+9) = ln (5x)If it is, the solution can be found by solving 2x+9 = 5x, in which case the answer is x = 3.
Solve or x 2 ln 9 plus 2 ln 5 equals 2 ln x minus 3?
2 ln(9) + 2 ln(5) = 2 ln(x) - 3ln(81) + ln(25) = ln(x2) - 37.61332 = ln(x2) - 3ln(x2) = 10.61332ln(x) = 5.30666x = e5.30666 = 201.676 (rounded)
What is the solution set of 2.5 to the power of 2x equals 8?
2.52x = 8 Taking (natural) logs: 2x*ln(2.5) = ln(8) so 2x = ln(8)/ln(2.5) = 2.0794/0.9163 = 2.2694 approx. and therefore, x = 2.2694/2 = 1.1347 approx.
What is the value of x given the equation 5 to the power of 1- 2 x equals 0.25 correct to 3 decimal places Please show working out?
51-2x = 0.25 51 * 5-2x = 0.25 5-2x = 0.05 -2x*ln(5) = ln(0.05) x = ln(0.05)/[-2*ln(5)] = 0.931
