The general form for the equation of a circle centre (xo, yo) and radius r is:
(x - xo)2 + (y - yo)2 = r2
Which can be rearranged into:
x2 - 2xox + y2 - 2yoy = r2 - xo2 - yo2
So a circle with centre (4, -1) and radius 8 has equations:
(x - 4)2 + (y + 1)2 = 64
x2 - 8x + y2 + 2y = 47
3.14 x 1
This makes no sence
The equation is: (x+1)^2 +(y+5)^2 = 36
(x - 1)2 + (y + 1)2 = 1
It is: (x+3)^2+(y-1)^2 = 25
3.14 x 1
This makes no sence
If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4
If you mean a circle center at (3, 1) and a radius of 2 then the equation of the circle is (x-3)^2 +(y-1)^2 = 4
A unit circle is a circle of radius 1. If it's center is at the origin of an xy-coordinate system, then the equation is x (squared) + y (squared) = 1
The equation is: (x+1)^2 +(y+5)^2 = 36
(x - 1)2 + (y + 1)2 = 1
(x + 2)2 + (y - 2)2 = 1
(x + 2)2 + (y - 2)2 = 1
It is: (x+3)^2+(y-1)^2 = 25
It is (x - 1)^2 + (y - 1)^2 = 5^2
(x + 1)2 + (y + 5)2 = 36