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What is the equation of the line that passes through 1 5 and 4 11?
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
What is the equation of the line that passes through the points (-42) and (4-2)?
If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x
What is the equation of the line that passes through the points 0 5 and 2 3?
Points: (0. 5) and (2, 3) Slope: -1 Equation: y = -x+5
Using the point slope formula what is the equation of the line that passes through the points 15 and 00?
If the points are (1,5) and (0,0) y = 5x
How do you write an equation of the line that passes through the points -3 -4 and 6 -1?
Points: (-3, -4) and (6, -1) Slope: 1/3 Equation: 3y = x-9
What is the equation of a line in general form that passes through points (-1 2) and (5 2)?
Points: (-1, 2) and (5, 2) Slope: 0 Equation: y = 2
Write the equation of the line that passes through the points 12 and 6 and 12 and -4?
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
What is the equation for a line that passes through the points (2-2) and (-422)?
If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6
Which is not an equation of the line that passes through the points 1 1 and 5 5?
The equation for the given points is y = x+4 in slope intercept form
What is the equation of a line that passes through points -1 2 and 5 2?
It is y = 2.
What equation of a line passes through the points 0'8 and 3'-1?
Y= -3x + 8
What is the equation of the line that passes through 1 5 and 4 11?
Plug both points into the equation of a line, y =m*x + b and then solve the system of equations for m and b to get equation of the line through the points.
How do you make a linear equation go through three points?
In general, a linear equation CANNOT be made to go through three points. That will only happen if the three points are collinear and in that case, the equation of the line will only require two points.
How do you find the equation of a tangent line?
In order to find the equation of a tangent line you must take the derivative of the original equation and then find the points that it passes through.
What is the equation of the line that passes through the points (-42) and (4-2)?
If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x
What is the equation of the line that passes through the points 0 5 and 2 3?
Points: (0. 5) and (2, 3) Slope: -1 Equation: y = -x+5
Which of the following is the equation of a line that passes through the points (06) and (210)?
Answer this question…y = 2x + 6
