(5, 5) and (2, 5)
Find slope first.
m(slope) = Y2 - Y1/X2 - X1
m = 5 - 5/2 - 5
m = 0
=======Now, point slope form. Use set of points; second set will do.
Y - Y1 = m(X - X1)
Y - 5 = 0(X - 2)
Y - 5 = X
Y = X + 5
=======
y = 5
The equation is x = 2
If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6
Points: 0 2 and 6 0 Equation: y = -1/3x+2
This is an equation of a line. There are an infinite number of solutions which are all points on the line. It is a linear equation.
y = 5
If you mean points of (-4, 2) and (4, -2) Then the straight line equation works out as 2y = -x
If you mean points of (2, -8) and (0, 0) then the equation is y = -4x
The equation is x = 2
Choose the equation of the line that contains the points (1, -1) and (2, -2).
If you mean points of (2, -2) and (-4, 22) then the equation is y = -4x+6
what is the slope of the line containing points (5-,-2) and (-5,3)? 2
Points: (0, -2) and (6, 0) Slope: 1/3 Equation of line: 3y = x-6
If you mean points of: (-1, 5) and (2, -4) Then the equation works out as: y = -3x+2
Points: 0 2 and 6 0 Equation: y = -1/3x+2
If you mean points of: (2, -8) and (0, 0) then the slope is -4 and equation is y = -4x
This is an equation of a line. There are an infinite number of solutions which are all points on the line. It is a linear equation.