To find the equation of the line that passes through the points of the arithmetic sequence defined by ( u_0 = 10 ) and ( u_{n-1} = -3 ) where ( n = 1 ), we first identify the two points: ( (0, 10) ) and ( (1, -3) ). The slope ( m ) of the line between these points is calculated as ( m = \frac{-3 - 10}{1 - 0} = -13 ). Using the point-slope form ( y - y_1 = m(x - x_1) ), we can write the equation as ( y - 10 = -13(x - 0) ), simplifying to ( y = -13x + 10 ).
The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
If it passes through the origin
y = 0. You can get this from the slope-intercept equation of the line.
y = 3x
If you mean a slope of -2 passing through (5, 0) then the equation is y = -2x+10
which equation has a slope of -1/2 and a graph that passes through (-3,4)?
Write the equation of the line that passes through the points (3, -5) and (-4, -5)
The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
If it passes through the origin
The equation is: y = 4x-22
y = 0. You can get this from the slope-intercept equation of the line.
y = 3x
It is: y = -2x
y = -4x
If you mean a slope of -2 passing through (5, 0) then the equation is y = -2x+10
sda
The equation works out as: y = 5x+7