y - x + 1 have no boundary as we don't know what x and y are.
I shouldn't say "no boundary", it's more of that the boundary is not defined.
If you mean y = x+5 and x is -1 then y = 4
To find the ordered pair for the expression ( y - x - 5 = yx + 1 ), we need to rearrange the equation. This can be rewritten as ( y - yx = x + 6 ) or ( y(1 - x) = x + 6 ). Solving for ( y ) gives ( y = \frac{x + 6}{1 - x} ). The ordered pair would depend on specific values of ( x ) and ( y ) that satisfy this equation. For example, if ( x = 0 ), then ( y = 6 ), yielding the ordered pair (0, 6).
There is no obvious simplification. A simple factorisation of the three terms is not possible. One possibility is to add another term and then factorise but that will always leave (at least) one term outside the factorisation. For example, x + yx + y = x + yx + y + 1 - 1 = (x + 1)(y + 1) - 1 The advantage of this form is that if you want the 0 of the original equation, it is equivalent to solving (x + 1)(y + 1) - 1 = 0 or (x + 1)(y + 1) = 1 which gives (x + 1) = 1/(y + 1)
The equation you provided, "yx - 3," is not in a standard linear form (y = mx + b), which makes it difficult to directly identify the slope. If you meant to express the equation as ( y = mx + b ), please clarify. If you intended to write ( y = x - 3 ), then the slope (m) is 1. If it's a different equation, please provide the correct format for an accurate response.
Yes.
There isn't any. " yx-1 " is not an equation.
If you mean y = x+5 and x is -1 then y = 4
It generates a hyperbolic paraboloid.
To find the ordered pair for the expression ( y - x - 5 = yx + 1 ), we need to rearrange the equation. This can be rewritten as ( y - yx = x + 6 ) or ( y(1 - x) = x + 6 ). Solving for ( y ) gives ( y = \frac{x + 6}{1 - x} ). The ordered pair would depend on specific values of ( x ) and ( y ) that satisfy this equation. For example, if ( x = 0 ), then ( y = 6 ), yielding the ordered pair (0, 6).
There is no obvious simplification. A simple factorisation of the three terms is not possible. One possibility is to add another term and then factorise but that will always leave (at least) one term outside the factorisation. For example, x + yx + y = x + yx + y + 1 - 1 = (x + 1)(y + 1) - 1 The advantage of this form is that if you want the 0 of the original equation, it is equivalent to solving (x + 1)(y + 1) - 1 = 0 or (x + 1)(y + 1) = 1 which gives (x + 1) = 1/(y + 1)
1 + 12 is not an equation.
y>x-1
The problem to solve is: xy+x+3y+3 Multiply y and x Multiply the y and x Multiply y and x The y just gets copied along. The x just gets copied along. The answer is yx yx x*y evaluates to yx x*y+x evaluates to yx+x Multiply y and 3 Multiply y and 1 The y just gets copied along. The answer is y y 3*y evaluates to 3y The answer is yx+x+3y x*y+x+3*y evaluates to yx+x+3y The answer is yx+x+3y+3 x*y+x+3*y+3 evaluates to yx+x+3y+3 ---- The final answer isyx+x+3y+3----
The equation you provided, "yx - 3," is not in a standard linear form (y = mx + b), which makes it difficult to directly identify the slope. If you meant to express the equation as ( y = mx + b ), please clarify. If you intended to write ( y = x - 3 ), then the slope (m) is 1. If it's a different equation, please provide the correct format for an accurate response.
-4x + 4y = 1
There is no solution since the equation is inconsistent.
The mathematical equation of 1 plus 4 plus 5 is equivalent to 10.