There is no obvious simplification. A simple factorisation of the three terms is not possible.
One possibility is to add another term and then factorise but that will always leave (at least) one term outside the factorisation. For example,
x + yx + y = x + yx + y + 1 - 1
= (x + 1)(y + 1) - 1
The advantage of this form is that if you want the 0 of the original equation, it is equivalent to solving
(x + 1)(y + 1) - 1 = 0
or (x + 1)(y + 1) = 1
which gives (x + 1) = 1/(y + 1)
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4xy + x3y + yx2 + yx + 3yx = x3y + x2y + 8xy = (xy)(x2y + x + 8)
If you mean y = x+5 and x is -1 then y = 4
If you mean: y = 4x-2 and y = x+13 then x = 5 and y = 18
yx * yx = y2x.Using the law of exponents, we add the 2 exponents, getting you 2x rather than just 'x'.
y = 0x = y + 2plug 0 in for yx = 0 + 2x = 2