To find the equation of the line passing through the points (3, 4) and (5, 8), we first calculate the slope (m) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Substituting the points, we get ( m = \frac{8 - 4}{5 - 3} = \frac{4}{2} = 2 ). Using the point-slope form ( y - y_1 = m(x - x_1) ), we can substitute one of the points, say (3, 4), to get ( y - 4 = 2(x - 3) ). Rearranging this into standard form ( Ax + By = C ), we find the equation is ( 2x - y = 2 ).
If you mean of points of (3, -4) and (5, 1) then the equation works out as 2y=5x-23
If you mean points of (-2, 4) and (3, 5) then its equation works out as 5y = x+22
The equation is x = 2
Points: 0 2 and 6 0 Equation: y = -1/3x+2
The formula for a line is: Y = mX + b
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If you mean of points of (3, -4) and (5, 1) then the equation works out as 2y=5x-23
If you mean points of (-2, 4) and (3, 5) then its equation works out as 5y = x+22
The equation is x = 2
Points: (4, 1) and (5, 2) Slope: 1 Equation: y = x-3 Equation in its general form: x-y-3 = 0
Points: (2, -3) and (-2, 0) Slope: -3/4 Equation: y = -0.75x-1.5
Points: 0 2 and 6 0 Equation: y = -1/3x+2
The formula for a line is: Y = mX + b
x = 2
The equation of the line passing through the points (mx, ny) and (2, 5) is y ((5-ny)/(2-mx))x (5 - ((5-ny)/(2-mx))2).
Points: (2, 2) and (3, 1) Slope: -1 Equation: y = -x+4
y = -1.125x + 2.25