Without an equality sign and not knowing the plus or minus values of y and 7 it can't be considered to be a straight line equation therefore finding its perpendicular equation is impossible.
Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3
If you mean 7 = 7x-3 then the perpendicular slope is -1/7 and the equation is y = -1/7x
2-3
Yes, I could, if I knew the slope of the line given.
Perpendicular slope: 1/2 Perpnedicular equation: y-5 = 1/2(x-2) => y = 0.5x+4
Perpendicular slope: -1/4 Perpendicular equation: y-0 = -1/4(x-3) => y = -0.25x+3
If you mean 7 = 7x-3 then the perpendicular slope is -1/7 and the equation is y = -1/7x
That would depend on its slope which has not been given.
General formula
2-3
That depends on the equation that it is perpendicular too which has not been given but both equations will meet each other at right angles.
Yes, I could, if I knew the slope of the line given.
Perpendicular slope: 1/2 Perpnedicular equation: y-5 = 1/2(x-2) => y = 0.5x+4
To determine the equation of a line that is perpendicular to another line and passes through the point (6, 2), we first need the slope of the original line. If the slope of the original line is ( m ), the slope of the perpendicular line will be ( -\frac{1}{m} ). Without the specific line's equation, we can't compute the exact perpendicular line. However, if you have options like A, B, etc., you can find the correct one by substituting the point (6, 2) into each equation to see which one satisfies it.
As for example the perpendicular equation to line y = 2x+6 could be y = -1/2x+6 because the negative reciprocal of 2x is -1/2x
Slope of line: 3 Perpendicular slope: -1/3 Equation: y-2 = -1/3(x-0) => y = -1/3x+2
A line that is perpendicular to the segment of a plane and passes through the midpoint.