If our two points were (x1,y1) and (x2,y2). We'd remember slope is rise over run. We'd have (y1-y2)/(x1-x2). Plug in your numbers, and you would have the slope of the line between these two points.
the slope is the 'm' in y=mx+b so even if the points aren't given, if there is an equation, then you can find the slope. for example, if you have an equation like this: y=2x+5 the slope is 2 and the y-intercept is 5.
To find the equation of a line, you can start by identifying two points on the line, each represented by their coordinates (x₁, y₁) and (x₂, y₂). You can then calculate the slope (m) using the formula ( m = \frac{y₂ - y₁}{x₂ - x₁} ). Once you have the slope, you can use the point-slope form of the equation ( y - y₁ = m(x - x₁) ) to derive the line's equation. Finally, this can be rearranged into the slope-intercept form ( y = mx + b ) if needed.
First, you calculate the slope between the two points (difference of y / difference of x). Then you can use the equation, using one of the points (x1, y1): y - y1 = m(x - x1) Just replace x1 and y1 with the coordinates of the point, and m with with the slope.
To determine the correct equation for the points (0, 1), (2, 5), and (3, 7), we can first find the slope between two of the points, for example, (0, 1) and (2, 5). The slope is (5 - 1) / (2 - 0) = 2. The equation of the line in slope-intercept form (y = mx + b) is then y = 2x + 1. This equation can be checked with the other points to confirm its validity.
To find a linear equation in slope-intercept form (y = mx + b), identify the slope (m) and the y-intercept (b) of the line. You can derive the slope from two points on the line using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Once you have the slope, substitute one of the points into the equation to solve for the y-intercept (b). Finally, plug both values into the slope-intercept form.
the slope is the 'm' in y=mx+b so even if the points aren't given, if there is an equation, then you can find the slope. for example, if you have an equation like this: y=2x+5 the slope is 2 and the y-intercept is 5.
Use the equation; y=mx+b where m is the slope Use your 2 points as y and b (intercept)
To find the equation of a line, you can start by identifying two points on the line, each represented by their coordinates (x₁, y₁) and (x₂, y₂). You can then calculate the slope (m) using the formula ( m = \frac{y₂ - y₁}{x₂ - x₁} ). Once you have the slope, you can use the point-slope form of the equation ( y - y₁ = m(x - x₁) ) to derive the line's equation. Finally, this can be rearranged into the slope-intercept form ( y = mx + b ) if needed.
First, you calculate the slope between the two points (difference of y / difference of x). Then you can use the equation, using one of the points (x1, y1): y - y1 = m(x - x1) Just replace x1 and y1 with the coordinates of the point, and m with with the slope.
To determine the correct equation for the points (0, 1), (2, 5), and (3, 7), we can first find the slope between two of the points, for example, (0, 1) and (2, 5). The slope is (5 - 1) / (2 - 0) = 2. The equation of the line in slope-intercept form (y = mx + b) is then y = 2x + 1. This equation can be checked with the other points to confirm its validity.
what is the slope of the line containing points (5-,-2) and (-5,3)? 2
To find a linear equation in slope-intercept form (y = mx + b), identify the slope (m) and the y-intercept (b) of the line. You can derive the slope from two points on the line using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Once you have the slope, substitute one of the points into the equation to solve for the y-intercept (b). Finally, plug both values into the slope-intercept form.
To find the equation of a line from a table of values, identify two points from the table, typically in the form (x, y). Use these points to calculate the slope (m) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). Once you have the slope, use one of the points and the point-slope form of the equation ( y - y_1 = m(x - x_1) ) to derive the line's equation. Finally, you can rearrange it into slope-intercept form ( y = mx + b ) if desired.
The slope-intercept form of a linear equation is expressed as ( y = mx + b ), where ( m ) represents the slope and ( b ) is the y-intercept. To find the specific equation for points (2, 4) and (5, 13), you first calculate the slope ( m ) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). For these points, the slope is ( m = \frac{13 - 4}{5 - 2} = 3 ). Using one of the points to find ( b ), we can write the equation as ( y = 3x - 2 ).
For two points at (x1,y1) and (x2,y2), respectively, the rate of change is equal to the slope of the shortest possible line segment connecting the two points. This slope can be calculated by the following equation: m = (y2-y1)/(x2-x1)
You have to differentiate the equation. The dy/dx is the slope.
To graph an equation that is not in slope-intercept form, you can use the process of finding points on the graph and plotting them. Choose a few x-values, plug them into the equation to find the corresponding y-values, and plot those points on the graph. Then, connect the points with a smooth line to complete the graph.