If our two points were (x1,y1) and (x2,y2). We'd remember slope is rise over run. We'd have (y1-y2)/(x1-x2). Plug in your numbers, and you would have the slope of the line between these two points.
the slope is the 'm' in y=mx+b so even if the points aren't given, if there is an equation, then you can find the slope. for example, if you have an equation like this: y=2x+5 the slope is 2 and the y-intercept is 5.
To find the equation of a line, you can start by identifying two points on the line, each represented by their coordinates (x₁, y₁) and (x₂, y₂). You can then calculate the slope (m) using the formula ( m = \frac{y₂ - y₁}{x₂ - x₁} ). Once you have the slope, you can use the point-slope form of the equation ( y - y₁ = m(x - x₁) ) to derive the line's equation. Finally, this can be rearranged into the slope-intercept form ( y = mx + b ) if needed.
First, you calculate the slope between the two points (difference of y / difference of x). Then you can use the equation, using one of the points (x1, y1): y - y1 = m(x - x1) Just replace x1 and y1 with the coordinates of the point, and m with with the slope.
To determine the correct equation for the points (0, 1), (2, 5), and (3, 7), we can first find the slope between two of the points, for example, (0, 1) and (2, 5). The slope is (5 - 1) / (2 - 0) = 2. The equation of the line in slope-intercept form (y = mx + b) is then y = 2x + 1. This equation can be checked with the other points to confirm its validity.
The slope-intercept form of a linear equation is expressed as ( y = mx + b ), where ( m ) represents the slope and ( b ) is the y-intercept. To find the specific equation for points (2, 4) and (5, 13), you first calculate the slope ( m ) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). For these points, the slope is ( m = \frac{13 - 4}{5 - 2} = 3 ). Using one of the points to find ( b ), we can write the equation as ( y = 3x - 2 ).
the slope is the 'm' in y=mx+b so even if the points aren't given, if there is an equation, then you can find the slope. for example, if you have an equation like this: y=2x+5 the slope is 2 and the y-intercept is 5.
Use the equation; y=mx+b where m is the slope Use your 2 points as y and b (intercept)
To find the equation of a line, you can start by identifying two points on the line, each represented by their coordinates (x₁, y₁) and (x₂, y₂). You can then calculate the slope (m) using the formula ( m = \frac{y₂ - y₁}{x₂ - x₁} ). Once you have the slope, you can use the point-slope form of the equation ( y - y₁ = m(x - x₁) ) to derive the line's equation. Finally, this can be rearranged into the slope-intercept form ( y = mx + b ) if needed.
First, you calculate the slope between the two points (difference of y / difference of x). Then you can use the equation, using one of the points (x1, y1): y - y1 = m(x - x1) Just replace x1 and y1 with the coordinates of the point, and m with with the slope.
To determine the correct equation for the points (0, 1), (2, 5), and (3, 7), we can first find the slope between two of the points, for example, (0, 1) and (2, 5). The slope is (5 - 1) / (2 - 0) = 2. The equation of the line in slope-intercept form (y = mx + b) is then y = 2x + 1. This equation can be checked with the other points to confirm its validity.
what is the slope of the line containing points (5-,-2) and (-5,3)? 2
You have to differentiate the equation. The dy/dx is the slope.
The slope-intercept form of a linear equation is expressed as ( y = mx + b ), where ( m ) represents the slope and ( b ) is the y-intercept. To find the specific equation for points (2, 4) and (5, 13), you first calculate the slope ( m ) using the formula ( m = \frac{y_2 - y_1}{x_2 - x_1} ). For these points, the slope is ( m = \frac{13 - 4}{5 - 2} = 3 ). Using one of the points to find ( b ), we can write the equation as ( y = 3x - 2 ).
For two points at (x1,y1) and (x2,y2), respectively, the rate of change is equal to the slope of the shortest possible line segment connecting the two points. This slope can be calculated by the following equation: m = (y2-y1)/(x2-x1)
To graph an equation that is not in slope-intercept form, you can use the process of finding points on the graph and plotting them. Choose a few x-values, plug them into the equation to find the corresponding y-values, and plot those points on the graph. Then, connect the points with a smooth line to complete the graph.
To find the slope between two points: slope = change_in_y/change_in_x Thus for the points (4, 5) and (6, 8), the slope between them is given by: slope = (8-5)/(6-4) = 3/2 = 1½ = 1.5
you should know this Find the difference of the y values over the difference in your x values to find the slope. Put it into the slope intercept form of the equation with one of the points substituted in and find the intercept. Rewrite the equation with the slope and the intercept. (-9-0)/(-3-0)=-9/-3=3 The slope. 27=3(9)+b 27=27+b 0=b Equation-> y=3x