the slope is the 'm' in y=mx+b so even if the points aren't given, if there is an equation, then you can find the slope. for example, if you have an equation like this: y=2x+5 the slope is 2 and the y-intercept is 5.
First, you calculate the slope between the two points (difference of y / difference of x). Then you can use the equation, using one of the points (x1, y1): y - y1 = m(x - x1) Just replace x1 and y1 with the coordinates of the point, and m with with the slope.
To graph an equation that is not in slope-intercept form, you can use the process of finding points on the graph and plotting them. Choose a few x-values, plug them into the equation to find the corresponding y-values, and plot those points on the graph. Then, connect the points with a smooth line to complete the graph.
Your x and y intercepts give you two points on the line of the graph. Use these two points in the slope equation m = (y2-y1)/(x2-x1), and that gives you the slope.
Find 2 points on the line, (x1,y1 ) (x2, y2) Slope = (y2 - y1)÷(x2-x1) In the equation of a line y = ax + b , a is the slope>
the slope is the 'm' in y=mx+b so even if the points aren't given, if there is an equation, then you can find the slope. for example, if you have an equation like this: y=2x+5 the slope is 2 and the y-intercept is 5.
Use the equation; y=mx+b where m is the slope Use your 2 points as y and b (intercept)
First, you calculate the slope between the two points (difference of y / difference of x). Then you can use the equation, using one of the points (x1, y1): y - y1 = m(x - x1) Just replace x1 and y1 with the coordinates of the point, and m with with the slope.
what is the slope of the line containing points (5-,-2) and (-5,3)? 2
You have to differentiate the equation. The dy/dx is the slope.
For two points at (x1,y1) and (x2,y2), respectively, the rate of change is equal to the slope of the shortest possible line segment connecting the two points. This slope can be calculated by the following equation: m = (y2-y1)/(x2-x1)
To find the slope between two points: slope = change_in_y/change_in_x Thus for the points (4, 5) and (6, 8), the slope between them is given by: slope = (8-5)/(6-4) = 3/2 = 1½ = 1.5
To graph an equation that is not in slope-intercept form, you can use the process of finding points on the graph and plotting them. Choose a few x-values, plug them into the equation to find the corresponding y-values, and plot those points on the graph. Then, connect the points with a smooth line to complete the graph.
Your x and y intercepts give you two points on the line of the graph. Use these two points in the slope equation m = (y2-y1)/(x2-x1), and that gives you the slope.
you should know this Find the difference of the y values over the difference in your x values to find the slope. Put it into the slope intercept form of the equation with one of the points substituted in and find the intercept. Rewrite the equation with the slope and the intercept. (-9-0)/(-3-0)=-9/-3=3 The slope. 27=3(9)+b 27=27+b 0=b Equation-> y=3x
how to find the slope of the line between the two points (-1,2) and (3, -6). can you plaese show how
Answer: When there is no slope stated in the function of x, when y=mx+b It simply means y=0x+b Since "b" is the y intercept, your line would be a horizontal line parallel to the X-axis passing through point (0,b) Answer: In other cases, you may need to calculate the slope first, from some other information provided. For example, if you are asked to find the equation that passes through two specified points, you can first find the slope between those two points. Then you can use this slope, and one of the points, with the slope-intercept form of the equation.