To find the factor of ( (x^2 + x - 17) ) divided by ( (x - 4) ), we can use polynomial long division. Dividing ( x^2 + x - 17 ) by ( x - 4 ) gives a quotient of ( x + 5 ) and a remainder of ( 3 ). Thus, we can express the division as ( x^2 + x - 17 = (x - 4)(x + 5) + 3 ). The factor of ( (x^2 + x - 17) ) in this context is ( x + 5 ) with a remainder of ( 3 ).
x+5 is a factor of x2+4x-5 use synthetic division to learn that the other factor is x-1
3x4 plus 5x3 plus x2 - 5 divided by x 2 =[(3x4) + (5x3) + (x2 - 5)]/x2 =(12 + 15 + x2 -5)/x2 =(27 - 5 + x2)/x2 =(22 + x2)/x2
x + 4
i got 42 divided 7x
x2 + 5x - 120 can not be factored.
x+5 is a factor of x2+4x-5 use synthetic division to learn that the other factor is x-1
3x4 plus 5x3 plus x2 - 5 divided by x 2 =[(3x4) + (5x3) + (x2 - 5)]/x2 =(12 + 15 + x2 -5)/x2 =(27 - 5 + x2)/x2 =(22 + x2)/x2
x2 - 161x + 51 doesn't factor. Applying the quadratic formula, we find two real solutions: (161 plus or minus the square root of 25717) divided by two.x = 160.6826040983953x = 0.3173959016046979
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
x + 4
x3 + 1 = (x + 1)(x2 - x + 1) The x + 1's cancel out, leaving x2 - x + 1
x2(x3 + 1) is the best you can do there.
Factor x2 plus 12xp plus 36p2 is (x+6p)(x+6p).
i got 42 divided 7x
That does not factor neatly.
You can't factor it
Not factorable