(2x - 3)*(4x2 + 6x + 9) = 0
It is: (5x-1)(5x+1) = 0 when factored
Do you mean: y2+13y+40 = 0 If so then when factored: (y+5)(y+8) = 0 Therefore: y = -5 and y = -8.
you would first do 10+5x-5=0, then 5x+5=0 and is factored by 5(x+1)=0. or if you want to know what x equals with, x=-1
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals". 8x3 + 27 = 0 => (2x + 3)*(4x2 - 6x + 9) = 0
It is sqrt(0), which equals 0.
(2x+1)(x+2) = 0
Im assuming the "6x2" is supposed to be 6x squared. The factored form would be (2x+1) (3x-8)
It is: (5x-1)(5x+1) = 0 when factored
(x-2)(3x+1)
7 and (-3/2)
Equation: 10x^2 -29x +10 = 0 When factored: (2x-5)(5x-2) = 0 Its solutions: x = 5/2 or x = 2/5
7x2-10x+3=0 (7x-3)(x-1)=0
Do you mean: y2+13y+40 = 0 If so then when factored: (y+5)(y+8) = 0 Therefore: y = -5 and y = -8.
you would first do 10+5x-5=0, then 5x+5=0 and is factored by 5(x+1)=0. or if you want to know what x equals with, x=-1
Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals". 8x3 + 27 = 0 => (2x + 3)*(4x2 - 6x + 9) = 0
It can not be factored because its discriminant is less than zero
x2-15x+56 = 0 (x-8)(x-7) = 0 Therefore: x = 8 or x = 7 To ensure that your answer is correct multiply out the brackets and you should go back to the original quadratic equation.