Q: What is the factored form of 8x3-27 equals 0?

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It is: (5x-1)(5x+1) = 0 when factored

Do you mean: y2+13y+40 = 0 If so then when factored: (y+5)(y+8) = 0 Therefore: y = -5 and y = -8.

you would first do 10+5x-5=0, then 5x+5=0 and is factored by 5(x+1)=0. or if you want to know what x equals with, x=-1

Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals". 8x3 + 27 = 0 => (2x + 3)*(4x2 - 6x + 9) = 0

If you mean: x2+9x+20 then it is (x+4)(x+5) = 0 when factored

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(2x+1)(x+2) = 0

Im assuming the "6x2" is supposed to be 6x squared. The factored form would be (2x+1) (3x-8)

It is: (5x-1)(5x+1) = 0 when factored

(x-2)(3x+1)

7 and (-3/2)

Equation: 10x^2 -29x +10 = 0 When factored: (2x-5)(5x-2) = 0 Its solutions: x = 5/2 or x = 2/5

Do you mean: y2+13y+40 = 0 If so then when factored: (y+5)(y+8) = 0 Therefore: y = -5 and y = -8.

you would first do 10+5x-5=0, then 5x+5=0 and is factored by 5(x+1)=0. or if you want to know what x equals with, x=-1

7x2-10x+3=0 (7x-3)(x-1)=0

Unfortunately, limitations of the browser used by Answers.com means that we cannot see most symbols. It is therefore impossible to give a proper answer to your question. Please resubmit your question spelling out the symbols as "plus", "minus", "times", "equals". 8x3 + 27 = 0 => (2x + 3)*(4x2 - 6x + 9) = 0

x2-15x+56 = 0 (x-8)(x-7) = 0 Therefore: x = 8 or x = 7 To ensure that your answer is correct multiply out the brackets and you should go back to the original quadratic equation.

It can not be factored because its discriminant is less than zero