(x-2)(3x+1)
It is: (5x-1)(5x+1) = 0 when factored
(2x - 3)*(4x2 + 6x + 9) = 0
(2x+1)(x+2) = 0
7 and (-3/2)
Equation: 10x^2 -29x +10 = 0 When factored: (2x-5)(5x-2) = 0 Its solutions: x = 5/2 or x = 2/5
7x2-10x+3=0 (7x-3)(x-1)=0
Do you mean: y2+13y+40 = 0 If so then when factored: (y+5)(y+8) = 0 Therefore: y = -5 and y = -8.
you would first do 10+5x-5=0, then 5x+5=0 and is factored by 5(x+1)=0. or if you want to know what x equals with, x=-1
Im assuming the "6x2" is supposed to be 6x squared. The factored form would be (2x+1) (3x-8)
It can not be factored because its discriminant is less than zero
There are 2 roots to the equation x2-4x-32 equals 0; factored it is (x-8)(x+4); therefore the roots are 8 & -4.
x2 - 8x + 15 = 0 can be factored as (x - 3)(x - 5) = 0 : This holds true when one or both of the terms in brackets equals zero. When x - 3 = 0 then x = 3 When x - 5 = 0 then x = 5.