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If the question is x2 + x = 56 then the factorisation is (x - 8)(x + 7)
If the question is x2 - x = 56 then the factorisation is (x + 8)(x - 7)
The prime factorization of 56 is:7 x 23 = 56
x2-7x+6 = (x-1)(x-6) when factored.
x2 + 4x - 32 = (x + 8)*(x - 4)
x2-x-56 = (x+7)(x-8) when factored
-x2 + 2x + 48 = (-x - 6)(x - 8)
y =x^2-x-56 is the same as y = (x + 7)(x - 8)
The prime factorization of 56 is:7 x 23 = 56
Assuming that x2 is x squared: (x - 9)(x + 4)
The factorization of 56 is 2 x 2 x 2 x 7. For it to be common, it would need to be compared to another factorization.
10x2 - 56 = 88 - 6x2 : 10x2 + 6x2 = 88 + 56 : 16x2 = 144 : x2 = 9 : x = ± 3
x2 - 8x - 40 = 0 ∴ x2 - 8x = 40 ∴ x2 - 8x + 16 = 56 ∴ (x - 4)2 = 56 ∴ x - 4 = ± 561/2 ∴ x = 4 ± 561/2 ∴ x = 4 ± 2 × 141/2 ∴ x ≈ {11.4833, -3.4833}
The prime factorization of 18 is 2 x 3 x 3. The prime factorization of 56 is 2 x 2 x 2 x7.
x2-15x+56 = 0 (x-8)(x-7) = 0 Therefore: x = 8 or x = 7 To ensure that your answer is correct multiply out the brackets and you should go back to the original quadratic equation.
This will only give a rational answer when it's +56. Then you're looking for two numbers that add to 15 and multiply to 56. That's 7 and 8. If it's -15x, the answer is (x - 8)(x - 7) If it's +15x, the answer is (x + 8)(x + 7)
X2 -11x +10=(x - 1 )(x - 10)
x2-7x+6 = (x-1)(x-6) when factored.
x2 + 4x - 32 = (x + 8)*(x - 4)