This will only give a rational answer when it's +56. Then you're looking for two numbers that add to 15 and multiply to 56. That's 7 and 8.
If it's -15x, the answer is (x - 8)(x - 7)
If it's +15x, the answer is (x + 8)(x + 7)
-(x + 5)(x + 6)
(x + 9)(x + 2)
x2 -11x-12= (x-12)(x+1)
(x+20)(x-5) x=5 or -20
x2+5x-14 = (x+7)(x-2) when factored
x2 + 15x +36
12
(x + 7)(x + 8)
-(x + 5)(x + 6)
(x + 9)(x + 2)
15x2 + 2x - 56 = 15x2 + 30x - 28x - 56 = 15x(x + 2) - 28(x + 2) = (15x - 28)(x + 2)
(x + 5)(x + 2)
The correct classification of x2 15x is a monomial.
x2-15x+56 = 0 (x-8)(x-7) = 0 Therefore: x = 8 or x = 7 To ensure that your answer is correct multiply out the brackets and you should go back to the original quadratic equation.
(x - 6)(x - 9)
(x - 4)(x - 11)
It is (x+2)(x+9) when factored