(4x-7)(3x+5) You can get this by using the formula method to find the two roots of the polynomial set equal to 0. Call them p and q. Then the answer is 12(x-p)(x-q) because you need to get the multiplier of x2 to be 12.
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(-4x + 3)(x - 2)Apex :)!!
x3 - 12x2 + 35x = x(x2 - 12x + 35) = x(x - 5)(x - 7)
3x3 - 24x2 + 45x = 3x*(x2 - 8x + 15) = 3x*(x - 3)*(x - 5)
3x3-18x2+24x=3x(x2-6x+8)=3x(x-4)(x-2)
Divide all terms by 4:- x2+7x+12 = (x+3)(x+4) when factored