tn = n2 - 3
Thus:
t1 = 12 - 3 = 1 - 3 = -2
t2 = 22 - 3 = 4 - 3 = 1
t3 = 32 - 3 = 9 - 3 = 6
t4 = 44 - 3 = 16 - 3 = 13
So the first four terms of n2 -3 are -2, 1, 6 & 13.
1, 4, 7, 10, 13, …
2x squared minus 4
2m^2 - 8 -First you should factor out a two. --> 2(m^2-4) -You now have something squared minus something else squared; You have m squared minus 2 squared. Whenever you have something squared minus something squared as you do in this case, there is a simple rule to remember: You can reduce that expression into the quantity of the square root of the first number or variable plus the square root of the second number or variable Times the quantity of the square root of the first number or variable minus the second number or variable squared. --> In the case of your expression: ----> 2(m+2)(m-2)<-----
No, unless "a" happens to be equal to 0, or to 1.
hello
1, 4, 7, 10, 13, …
This sequence is the result of 3 functions one after the other. These functions are: squared, add 2, minus 1. So 1 squared = 1, +2 = 3, -1 = 2, squared = 4, +2 = 6, -1 = 5, squared = 25.... So the next step would be +2 to get 27, then minus 1 to get 26.
3x squared minus 25x minus 28
2x squared minus 4
2m^2 - 8 -First you should factor out a two. --> 2(m^2-4) -You now have something squared minus something else squared; You have m squared minus 2 squared. Whenever you have something squared minus something squared as you do in this case, there is a simple rule to remember: You can reduce that expression into the quantity of the square root of the first number or variable plus the square root of the second number or variable Times the quantity of the square root of the first number or variable minus the second number or variable squared. --> In the case of your expression: ----> 2(m+2)(m-2)<-----
No, unless "a" happens to be equal to 0, or to 1.
-22 - -22
x = ? 42 = x squared minus x
hello
(9y+2z)(y-3z)
2x squared minus 5x minus 3 factored is (2x+1)(x-3).
sin squared