a^7 - b^7 = (a - b)(a^6 + a^5.b + a^4.b^2 + a^3.b^3 + a^2.b^4 +a.b^5 + b^6)
When the equation is a polynomial whose highest order (power) is 2. Eg. y= x2 + 2x + 10. Then you can use quadratic formula to solve if factoring is not possible.
So far there has been no formulas found. The randomness of prime numbers make them unpredictable to calculate. There is a bit of a hit and miss formula, which is (2 to the power of p) - 1, with p being a prime number. Prime numbers that fit this are callled "Mersenne primes". Mathematicians are still searching for a formula that works 100% of the time though. =)
There really isn't much to simplify there. You might consider it as the difference of two squares - the square of x1/4 and the square of 11/4 (or simply the square of 1), but factoring that will get you an expression that is more complicated, not simpler, than the original.
There is a formula for the "difference of squares." In this case, the answer is (x2 - 5)(x2 + 5)
That's the difference of the monomials' squares. If the two numbers are "a" and "b" then (a + b)(a - b) = a^2 - b^2 where ^ means "to the power of".
When the equation is a polynomial whose highest order (power) is 2. Eg. y= x2 + 2x + 10. Then you can use quadratic formula to solve if factoring is not possible.
The basic formula for factoring the difference between two perfect cubes is (a3 - b3) = (a - b)(a2 + ab + b2). Substituting the given polynomial yields (27x3 - 8) = (3x - 2)(9x2 + 6x + 4).
You start by using the difference of squares: x24 - 1 = (x12 + 1)(x12 - 1) The second term is again a difference of squares, so you can apply this special factoring once again.
The transmission capacity is based on a formula describing the power between a transmitter and a receiver. The ratio of these two numbers and the formula describes the capacity of the channel.
The transmission capacity is based on a formula describing the power between a transmitter and a receiver. The ratio of these two numbers and the formula describes the capacity of the channel.
the formula for power is work/time.
There is a formula for the "difference of squares." In this case, the answer is (x7 - 7)(x7 + 7)
So far there has been no formulas found. The randomness of prime numbers make them unpredictable to calculate. There is a bit of a hit and miss formula, which is (2 to the power of p) - 1, with p being a prime number. Prime numbers that fit this are callled "Mersenne primes". Mathematicians are still searching for a formula that works 100% of the time though. =)
There really isn't much to simplify there. You might consider it as the difference of two squares - the square of x1/4 and the square of 11/4 (or simply the square of 1), but factoring that will get you an expression that is more complicated, not simpler, than the original.
There is a formula for the "difference of squares." In this case, the answer is (x2 - 5)(x2 + 5)
That's the difference of the monomials' squares. If the two numbers are "a" and "b" then (a + b)(a - b) = a^2 - b^2 where ^ means "to the power of".
two numbers whose difference is equal to 4 to the power of 2 from the following numbers15 ,75.03,803,451,299,40.03