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The basic formula for factoring the difference between two perfect cubes is
(a3 - b3) = (a - b)(a2 + ab + b2).
Substituting the given polynomial yields
(27x3 - 8) = (3x - 2)(9x2 + 6x + 4).
Wiki User
∙ 10y ago
Wiki User
∙ 8y ago(3x - 2)(9x^2 + 6x + 4)
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Simplify 8 to the 3rd power x 8 to the 4th power?
320,000
What is the power of number 8?
if it is to the 2nd power it is 64 if it is to the 3rd power it is 512 .
What two to the third power equal?
2 to the 3rd power = 8
How does 2 to the third power equal 8?
2 to the 3rd power = 2 * 2 * 2 = 8
2 raised to the 3rd power?
23 = 8
How do you factor 8 minus 27x cubed?
(2 - 3x)(9x^2 + 6x + 4)
How do you factor 20x squared minus 27x minus 8?
20x2 - 27x -8 20 * -8 is -160, and -32 and 5 add to -27 20x2 - 32x + 5x - 8 4x(5x-8) + 1(5x-8) (4x + 1)(5x-8)
How do you factor the expression 27x cubed plus 8?
the answer is (3x-2)(9x squared+6x+4)
What is 8 divided by the square root of 27x?
0.2963
Factor 24x cubed plus 27x squared - 8 x - 9?
I also need to know the answer to this problem. Can anyone answer it?
What is the factored form of 27x cubed minus eight?
27X^3-8 = 0 27X^3 = 8 X^3 = 8/27 X = cubic root of 8/cubic root of 27 = 2/3
How do you factor 8 x to the 3rd power -125?
(2x - 5)(4x^2 + 10x + 25)
Prime factorization 8 27?
The prime factorization of 8 is 2^3. The prime factorization of 27 is 9 x 3.
Simplify 8 to the 3rd power x 8 to the 4th power?
320,000
How do you factor 10x2 plus 27x - 28?
To factor: 10x2 + 27x - 28 Find two values that add up to 27, our middle coefficient, and which multiply to make -280, the product of the other two coefficients. In this case, those two values would be 35 and -8. Now break the middle term down with those two values, and factor: = 10x2 + 35x - 8x - 28 = 5x(2x + 7) - 4(2x + 7) = (5x - 4)(2x + 7)
What is the power of 2 that equals 8?
2 to the 3rd power.
What is the power of number 8?
if it is to the 2nd power it is 64 if it is to the 3rd power it is 512 .
