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What is the general form of a straight line equation perpendicular to 4x plus 3y minus 5 equals 0 passing through a point minus 2 and minus 3 on the line?
Equation of original line is 4x + 3y - 5 = 0
that is, 3y = -4x + 5
or y = -(4/3)x + 5
Slope of original line = -4/3
Slope of line perpendicular to it = 3/4
General equation of perpendicular line: y = (3/4)x + c for some constant c
or 4y = 3x + c'
The point (-2,-3) is on this line so 4*(-3) = 3*(-2) + c'
-12 = - 6 + c' so that c' = -6
The equation of the perpendicular line is 4y = 3x - 6
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What is the straight line equation in its general form passing through the points 1 3 and -19 -19?
The general form is 11x - 10y + 19 = 0
What is the equation passing through the point 3 -4 which is perpendicular to the line 5x -2y equals 3?
Known equation: 5x-2y = 3 or y = 5/2x -3/2 Slope of known equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y- -4 = -2/5(x-3) => 5y =-2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
What is the straight line equation passing through the point 4 0 and perpendicular to the line x plus 7y plus 4 equals 0?
7x-y-28 = 0
Find the slope and y - intercept of the linear equation 5x-10 equals -20?
5x - 10 = -20This equation can be restated as 5x = -10 : x = -2This is the equation of a straight line perpendicular to the x axis and passing through the point x = -2. There is no y intercept and the slope is indeterminate.
What does state the equation of the straight line with a gradient of 2 passing through the y axis at 0 4?
It is the equation of a straight line in the form of: y = 2x+4
What is the equation of the line passing through 3 -4 and it is perpendicular to the line 5x -2y equals 3?
Known equation: 5x -2y = 3 or y = 5/2x -3/2 Slope of equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y --4 = -2/5(x -3) => 5y = -2x -14 Perpendicular equation in its general form: 2x+5y+14 = 0
What is the equation of the line passing through -2 -3 that is at right angles to the equation 4x plus 3y -5 equals 0 on the Cartesian plane?
The equation will be perpendicular to the given equation and have a slope of 3/4:- Perpendicular equation: y--3 = 3/4(x--2) => 4y--12 = 3x--6 => 4y = 3x-6 Perpendicular equation in its general form: 3x-4y-6 = 0
What is the straight line equation in its general form passing through the points 1 3 and -19 -19?
The general form is 11x - 10y + 19 = 0
What is the equation passing through the point 3 -4 which is perpendicular to the line 5x -2y equals 3?
Known equation: 5x-2y = 3 or y = 5/2x -3/2 Slope of known equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y- -4 = -2/5(x-3) => 5y =-2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
What is the straight line equation passing through the point -2 -3 and perpendicular to the line 4x plus 3y minus 5 equals 0?
3x-4y-6 = 0
What is the straight line equation passing through the point 4 0 and perpendicular to the line x plus 7y plus 4 equals 0?
7x-y-28 = 0
Find the slope and y - intercept of the linear equation 5x-10 equals -20?
5x - 10 = -20This equation can be restated as 5x = -10 : x = -2This is the equation of a straight line perpendicular to the x axis and passing through the point x = -2. There is no y intercept and the slope is indeterminate.
What equation represents a line perpendicular to y equals x and passing through the points 0 0?
y=-x
What does state the equation of the straight line with a gradient of 2 passing through the y axis at 0 4?
It is the equation of a straight line in the form of: y = 2x+4
What is the perpendicular bisector equation passing between the points 3 -4 and -1 -2?
Points: (3,-4) and (-1, -2) Midpoint: (1,-3) Slope: -1/2 Perpendicular slope: 2 Perpendicular bisector equation in slope intercept form: y = 2x-5
What is the equation of the straight line passing through the point 4 -2 and perpendicular to the line whose equation is 2x -y -5 equals 0?
2x-y -5 = 0 => y = 2x -5 The perpendicular slope is the negative reciprocal of 2 which is -1/2 So using the formula of y -y1 = m(x -x1) gives the straight line equation:- y - -2 = -1/2(x -4) y +2 = -1/2x +2 y = -1/2x +2 -2 y = -1/2x which can be expressed in the form of: x +2y = 0 So the straight line equation is: x +2y = 0
What in its general form is the perpendicular bisector equation passing through the line segment of h k and 3h -5k showing key stages of your work?
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