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Where is the center of the circle given by the equation x plus 5 times 2 plus y - 3 times 2 equals 25 in an ordered pair?
Exactly as it's stated, that equation describes a straight line, not a circle. If you take out the phrase "times 2" from both places where it's used and replace it with "squared", then the equation describes a circle, centered at (-5, 3), with a radius of 5.
Where is the center of the circle given by the equation x plus 5 squared plus y minus 3 equals 25 Enter your answer as an ordered pair?
It's at the point ( -5, 3 ) The general formula of a circle is given by the equation: ( x - h )2 + ( y - k )2 = r2 Where the point ( h, k ) is the center of the circle, and r is the radius of the circle. In the equation ( x + 5 )2 + ( y - 3 )2 = 25 The first group of terms isn't subtracted. Rather than x + 5, this is actually x - -5. The center of the circle, then, is the point ( -5, 3 )
What is General equation of a line?
The general equation to represent a line isaX + bY = c, where a, b, and c are given values or parameters.See the reference for more information.
How do you figure square feet using a circumference?
Square feet are a measure of area, and the area of a circle is usually given by the equation: a = πr2 The circumference of a circle is given with the equation: c = 2πr To find the area of the circle given only it's circumference, we can rearrange the circumference equation, solving it for r, and then substituting it into our radius equation in place of r. c = 2πr r = c / 2π a = πr2 a = π(c / 2π)2 a = πc2 / 4π2 a = c2/π So the area of a circle is equal to the square of it's circumference divided by pi.
What is the center of the circle given by the equation x minus 2 times 2 plus y plus 4 times 2 equals 6?
What is the center of the circle given by the equation (x- 2)2 + (y + 4)2 = 6?(2, -4)
If a circle is centered at the origin and the length of its radius is 6 What is the circle's equation?
The general equation of a circle is given by the formula(x - h)2 + (x - k)2 = r2, where (h, k) is the center of the circle, and r its radius.Since the center of the circle is (0, 0), the equation reduces tox2 + y2 = r2So that the equation of our circle is x2 + y2 = 36.
The set of all points in a plane equidistant from a given point?
a circle, centered at the given point.
Where is the center of the circle given by the equation x plus 5 times 2 plus y - 3 times 2 equals 25 in an ordered pair?
Exactly as it's stated, that equation describes a straight line, not a circle. If you take out the phrase "times 2" from both places where it's used and replace it with "squared", then the equation describes a circle, centered at (-5, 3), with a radius of 5.
Given the three numbers z1 z2 z3 show that these complex numbers are vertices of an equilateral triangle inscribed in a circle centered at the origin and radius r?
You cannot show it in general since it need not be true!
Where is the center of the circle given by the equation x plus 5 squared plus y minus 3 equals 25 Enter your answer as an ordered pair?
It's at the point ( -5, 3 ) The general formula of a circle is given by the equation: ( x - h )2 + ( y - k )2 = r2 Where the point ( h, k ) is the center of the circle, and r is the radius of the circle. In the equation ( x + 5 )2 + ( y - 3 )2 = 25 The first group of terms isn't subtracted. Rather than x + 5, this is actually x - -5. The center of the circle, then, is the point ( -5, 3 )
Where is the center of the circle given by the equation x - 3 squared plus y plus 2 squared equals 9?
The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).
What is General equation of a line?
The general equation to represent a line isaX + bY = c, where a, b, and c are given values or parameters.See the reference for more information.
How do you figure square feet using a circumference?
Square feet are a measure of area, and the area of a circle is usually given by the equation: a = πr2 The circumference of a circle is given with the equation: c = 2πr To find the area of the circle given only it's circumference, we can rearrange the circumference equation, solving it for r, and then substituting it into our radius equation in place of r. c = 2πr r = c / 2π a = πr2 a = π(c / 2π)2 a = πc2 / 4π2 a = c2/π So the area of a circle is equal to the square of it's circumference divided by pi.
What is the center of the circle given by the equation x minus 2 times 2 plus y plus 4 times 2 equals 6?
What is the center of the circle given by the equation (x- 2)2 + (y + 4)2 = 6?(2, -4)
I have a maths question i dont get please help me!"Describe fully the graph which has the equation x² + y² = 16."?
It's a circle. The equation of a circle is x^2+y^2=r^2. So the equation you've given is a circle with a radius of 4 and, since there are no modifications to the x or y values, the center of the circle is located at (0,0).
How do you find the area of a circle if the diameter is given?
multiple the diameter by 2 to get the radius, then use your equation and go from there
What is the equation of the circle with center -4 and 3 and radius 6?
the general equation of the circle is (x-a)^2+(y-b)^2=r^2 where (a,b) is the center of the circle. r is the radius of the circle substituting the given values, (x+4)^2+(y-3)^2=6^2 x^2+y^2+8x-6y+16+9=36 x^2+y^2+8x-6y=11
