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The circle is centered at the origin and the length of its radius is 10. what is the circle equation?
The equation of a circle centered at the origin with a radius ( r ) is given by the formula ( x^2 + y^2 = r^2 ). In this case, since the radius is 10, the equation becomes ( x^2 + y^2 = 10^2 ). Therefore, the equation of the circle is ( x^2 + y^2 = 100 ).
Which is the standard equation for a circle centered at origin with raduis r?
The standard equation for a circle centered at the origin (0, 0) with radius ( r ) is given by ( x^2 + y^2 = r^2 ). In this equation, ( x ) and ( y ) represent the coordinates of any point on the circle, and ( r ) is the radius. This equation describes all points that are a distance ( r ) from the center.
How To find the standard equation for a circle centered at the origin we use the distance formula since the radius measures?
To find the standard equation for a circle centered at the origin, we use the distance formula to define the radius. The equation is derived from the relationship that the distance from any point ((x, y)) on the circle to the center ((0, 0)) is equal to the radius (r). Thus, the standard equation of the circle is given by (x^2 + y^2 = r^2). Here, (r) is the radius of the circle.
Which is the standard equation for a circle centered at the origin with the radius r?
The standard equation for a circle centered at the origin with a radius ( r ) is given by the formula ( x^2 + y^2 = r^2 ). In this equation, ( (x, y) ) represents any point on the circle, and ( r ) is the distance from the center to any point on the perimeter. This equation describes all points that are exactly ( r ) units away from the origin (0, 0).
How do you find the equation of a circle centered at the origin given the radius 2?
The equation of a circle centered at the origin (0,0) can be expressed using the formula (x^2 + y^2 = r^2), where (r) is the radius. Given that the radius is 2, you substitute (r) into the formula: (x^2 + y^2 = 2^2). This simplifies to (x^2 + y^2 = 4). Thus, the equation of the circle is (x^2 + y^2 = 4).
If a circle is centered at the origin and the length of its radius is 6 What is the circle's equation?
The general equation of a circle is given by the formula(x - h)2 + (x - k)2 = r2, where (h, k) is the center of the circle, and r its radius.Since the center of the circle is (0, 0), the equation reduces tox2 + y2 = r2So that the equation of our circle is x2 + y2 = 36.
The circle is centered at the origin and the length of its radius is 10. what is the circle equation?
The equation of a circle centered at the origin with a radius ( r ) is given by the formula ( x^2 + y^2 = r^2 ). In this case, since the radius is 10, the equation becomes ( x^2 + y^2 = 10^2 ). Therefore, the equation of the circle is ( x^2 + y^2 = 100 ).
Which is the standard equation for a circle centered at origin with raduis r?
The standard equation for a circle centered at the origin (0, 0) with radius ( r ) is given by ( x^2 + y^2 = r^2 ). In this equation, ( x ) and ( y ) represent the coordinates of any point on the circle, and ( r ) is the radius. This equation describes all points that are a distance ( r ) from the center.
The set of all points in a plane equidistant from a given point?
a circle, centered at the given point.
Where is the center of the circle given by the equation x plus 5 times 2 plus y - 3 times 2 equals 25 in an ordered pair?
Exactly as it's stated, that equation describes a straight line, not a circle. If you take out the phrase "times 2" from both places where it's used and replace it with "squared", then the equation describes a circle, centered at (-5, 3), with a radius of 5.
Given the three numbers z1 z2 z3 show that these complex numbers are vertices of an equilateral triangle inscribed in a circle centered at the origin and radius r?
You cannot show it in general since it need not be true!
Where is the center of the circle given by the equation x plus 5 squared plus y minus 3 equals 25 Enter your answer as an ordered pair?
It's at the point ( -5, 3 ) The general formula of a circle is given by the equation: ( x - h )2 + ( y - k )2 = r2 Where the point ( h, k ) is the center of the circle, and r is the radius of the circle. In the equation ( x + 5 )2 + ( y - 3 )2 = 25 The first group of terms isn't subtracted. Rather than x + 5, this is actually x - -5. The center of the circle, then, is the point ( -5, 3 )
Where is the center of the circle given by the equation x - 3 squared plus y plus 2 squared equals 9?
The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).
What is General equation of a line?
The general equation to represent a line isaX + bY = c, where a, b, and c are given values or parameters.See the reference for more information.
How do you figure square feet using a circumference?
Square feet are a measure of area, and the area of a circle is usually given by the equation: a = πr2 The circumference of a circle is given with the equation: c = 2πr To find the area of the circle given only it's circumference, we can rearrange the circumference equation, solving it for r, and then substituting it into our radius equation in place of r. c = 2πr r = c / 2π a = πr2 a = π(c / 2π)2 a = πc2 / 4π2 a = c2/π So the area of a circle is equal to the square of it's circumference divided by pi.
What is the center of the circle given by the equation x minus 2 times 2 plus y plus 4 times 2 equals 6?
What is the center of the circle given by the equation (x- 2)2 + (y + 4)2 = 6?(2, -4)
I have a maths question i dont get please help me!"Describe fully the graph which has the equation x² + y² = 16."?
It's a circle. The equation of a circle is x^2+y^2=r^2. So the equation you've given is a circle with a radius of 4 and, since there are no modifications to the x or y values, the center of the circle is located at (0,0).
