The equation of a circle centered at the origin with a radius ( r ) is given by the formula ( x^2 + y^2 = r^2 ). In this case, since the radius is 10, the equation becomes ( x^2 + y^2 = 10^2 ). Therefore, the equation of the circle is ( x^2 + y^2 = 100 ).
The standard equation for a circle centered at the origin (0, 0) with radius ( r ) is given by ( x^2 + y^2 = r^2 ). In this equation, ( x ) and ( y ) represent the coordinates of any point on the circle, and ( r ) is the radius. This equation describes all points that are a distance ( r ) from the center.
To find the standard equation for a circle centered at the origin, we use the distance formula to define the radius. The equation is derived from the relationship that the distance from any point ((x, y)) on the circle to the center ((0, 0)) is equal to the radius (r). Thus, the standard equation of the circle is given by (x^2 + y^2 = r^2). Here, (r) is the radius of the circle.
The standard equation for a circle centered at the origin with a radius ( r ) is given by the formula ( x^2 + y^2 = r^2 ). In this equation, ( (x, y) ) represents any point on the circle, and ( r ) is the distance from the center to any point on the perimeter. This equation describes all points that are exactly ( r ) units away from the origin (0, 0).
The equation of a circle centered at the origin (0,0) can be expressed using the formula (x^2 + y^2 = r^2), where (r) is the radius. Given that the radius is 2, you substitute (r) into the formula: (x^2 + y^2 = 2^2). This simplifies to (x^2 + y^2 = 4). Thus, the equation of the circle is (x^2 + y^2 = 4).
The general equation of a circle is given by the formula(x - h)2 + (x - k)2 = r2, where (h, k) is the center of the circle, and r its radius.Since the center of the circle is (0, 0), the equation reduces tox2 + y2 = r2So that the equation of our circle is x2 + y2 = 36.
The equation of a circle centered at the origin with a radius ( r ) is given by the formula ( x^2 + y^2 = r^2 ). In this case, since the radius is 10, the equation becomes ( x^2 + y^2 = 10^2 ). Therefore, the equation of the circle is ( x^2 + y^2 = 100 ).
The standard equation for a circle centered at the origin (0, 0) with radius ( r ) is given by ( x^2 + y^2 = r^2 ). In this equation, ( x ) and ( y ) represent the coordinates of any point on the circle, and ( r ) is the radius. This equation describes all points that are a distance ( r ) from the center.
To find the standard equation for a circle centered at the origin, we use the distance formula to define the radius. The equation is derived from the relationship that the distance from any point ((x, y)) on the circle to the center ((0, 0)) is equal to the radius (r). Thus, the standard equation of the circle is given by (x^2 + y^2 = r^2). Here, (r) is the radius of the circle.
The standard equation for a circle centered at the origin with a radius ( r ) is given by the formula ( x^2 + y^2 = r^2 ). In this equation, ( (x, y) ) represents any point on the circle, and ( r ) is the distance from the center to any point on the perimeter. This equation describes all points that are exactly ( r ) units away from the origin (0, 0).
The equation of a circle centered at the origin (0,0) can be expressed using the formula (x^2 + y^2 = r^2), where (r) is the radius. Given that the radius is 2, you substitute (r) into the formula: (x^2 + y^2 = 2^2). This simplifies to (x^2 + y^2 = 4). Thus, the equation of the circle is (x^2 + y^2 = 4).
The equation of a circle centered at the origin (0, 0) with a radius of 15 is given by the formula ( x^2 + y^2 = r^2 ), where ( r ) is the radius. Substituting the radius, the equation becomes ( x^2 + y^2 = 15^2 ). Therefore, the equation simplifies to ( x^2 + y^2 = 225 ).
The general form of the equation of a circle with center at the point ( (a, b) ) and a radius of length ( m ) is given by the equation ( (x - a)^2 + (y - b)^2 = m^2 ). Here, ( (x, y) ) represents any point on the circle. This equation expresses that the distance from any point on the circle to the center ( (a, b) ) is equal to the radius ( m ).
a circle, centered at the given point.
Exactly as it's stated, that equation describes a straight line, not a circle. If you take out the phrase "times 2" from both places where it's used and replace it with "squared", then the equation describes a circle, centered at (-5, 3), with a radius of 5.
The equation of the circle is given by ((x - 6)^2 + (y + 5)^2 = 152). The general form of a circle's equation is ((x - h)^2 + (y - k)^2 = r^2), where ((h, k)) is the center and (r) is the radius. From the equation, the coordinates of the center of the circle are ((6, -5)).
To draw a flowchart for finding the equation of a circle passing through three given points, start by defining the three points as ( A(x_1, y_1) ), ( B(x_2, y_2) ), and ( C(x_3, y_3) ). Next, set up the general equation of a circle ( (x - h)^2 + (y - k)^2 = r^2 ) and derive a system of equations by substituting the coordinates of the points into this equation. Solve the resulting system of equations for the center coordinates ( (h, k) ) and the radius ( r ), and finally, express the equation of the circle in standard form.