The answer depends on where points b and c are!
The answer depends on the information that you have about the four points and the manner in which that information is presented. Suppose the 4 points are A, B, C and D and the point that you find is P. If you have the coordinates of A, B, C and D then gradient AP = gradient AB (or any other pair) will suffice. If you have any one of vectors AB (or AC, AD, BC, BD), then vector AP is parallel to vector AB will suffice.
Establishing equivalence depends on the definition of parallel lines. If they are defined as lines which cannot ever meet (have no point in common), then the relation is not reflexive and so cannot be an equivalence relation.However, if the lines are in a coordinate plane and parallel lines are defined as those which have the same gradient then:the gradient of a is the gradient of a so the relationship is reflexive ie a ~ a.if the gradient of a is m then b is parallel to a if gradient of b = m and, if the gradient of b is m then b is parallel to a. Thus the relation ship is symmetric ie a ~ b b ~ a.If the gradient of a is m then b is parallel to a if and only if gradient of b = gradient of a, which is m. Also c is parallel to b if and only if gradient of c = gradient of b which is m. Therefore c is parallel to a. Thus the relation is transitive, that is a ~ b and b ~ c => a ~ c.The relation is reflexive, symmetric and transitive and therefore it is an equivalence relationship.
It is a straight line with gradient -A/B and intercept C/B.
If points B and C are collinear, it means that they lie on the same straight line. To determine if points B and C are collinear, you would need to know the coordinates or have a visual representation of the points.
Probably an arc, but it is not possible to be certain because there is no information on where or what point b and c are..
The answer depends on where points b and c are!
.75 V
The answer depends on the information that you have about the four points and the manner in which that information is presented. Suppose the 4 points are A, B, C and D and the point that you find is P. If you have the coordinates of A, B, C and D then gradient AP = gradient AB (or any other pair) will suffice. If you have any one of vectors AB (or AC, AD, BC, BD), then vector AP is parallel to vector AB will suffice.
Establishing equivalence depends on the definition of parallel lines. If they are defined as lines which cannot ever meet (have no point in common), then the relation is not reflexive and so cannot be an equivalence relation.However, if the lines are in a coordinate plane and parallel lines are defined as those which have the same gradient then:the gradient of a is the gradient of a so the relationship is reflexive ie a ~ a.if the gradient of a is m then b is parallel to a if gradient of b = m and, if the gradient of b is m then b is parallel to a. Thus the relation ship is symmetric ie a ~ b b ~ a.If the gradient of a is m then b is parallel to a if and only if gradient of b = gradient of a, which is m. Also c is parallel to b if and only if gradient of c = gradient of b which is m. Therefore c is parallel to a. Thus the relation is transitive, that is a ~ b and b ~ c => a ~ c.The relation is reflexive, symmetric and transitive and therefore it is an equivalence relationship.
The answer may just depend on what points B and C represent, don't you think?
It is a straight line with gradient -A/B and intercept C/B.
A parabola is (mathematically speaking) a quadratic function, which looks like this y = ax2 + bx + c where a, b and c are constants. (If three points on the curve are known, then a, b and c can be found.) The gradient, then, can be found by differentiation: dy/dx = 2ax + b A parabola has one maximal or minimal point, where the gradient is zero. 2ax + b = 0 x = -b/2a Use the original function to find the corresponding value of y: y = a(-b/2a)2 + b(-b/2a) + c = b2/4a - b2/2a + c = c - b2/4a So the coordinates of your turning point are ( -b/2a , c - b2/4a ) This result can also be derived by completing the square.
If points B and C are collinear, it means that they lie on the same straight line. To determine if points B and C are collinear, you would need to know the coordinates or have a visual representation of the points.
exactly one
The negation of B is not between A and C is = [(A < B < C) OR (C < B < A)] If A, B and C are numbers, then the above can be simplified to (B - A)*(C - B) > 0
The Law of Cosines: c^2=a^2 + b^2 -2abcos(ab) , c is the distance between the two points a and b and (ab) is the angle between a and b from the origin. If one point is taken as the origin, and a and b a re taken at right angles to each other, then cos(ab) is zero and you have Pythagora' Theorem..