The square is.
90.25 ft2
You'd need to know one of the sides.
42 square units.
42.25 cm2
The greatest area for a fixed perimeter will be when all the sides are equal or when the rectangle approaches the shape of a square.
The square is.
90.25 ft2
The greatest area that a rectangle can have is, in fact, attained when it is a square. A square with perimeter of 16 cm must have sides of 4 cm and so an area of 4*4 = 16 cm2.
It's greatest possible perimeter: 1+39+1+39 = 80 feet
You'd need to know one of the sides.
42 square units.
You dont
81 square feet.
42.25 cm2
Assuming that you have a rectangle shaped area, 20 yards long by 15 yards wide, and you want to completely enclose the area with the fencing, then you have a problem where you need to find the perimeter of a rectangle. Perimeter = 2 * Length + 2 * Width Perimeter = 2 * (20 yd) + 2 * (15 yd) = 40 yd + 30 yd = 70 yards
This question has no unique answer. A (3 x 2) rectangle has a perimeter = 10, its area = 6 A (4 x 1) rectangle also has a perimeter = 10, but its area = 4 A (4.5 x 0.5) rectangle also has a perimeter = 10, but its area = 2.25. The greatest possible area for a rectangle with perimeter=10 occurs if the rectangle is a square, with all sides = 2.5. Then the area = 6.25. You can keep the same perimeter = 10 and make the area anything you want between zero and 6.25, by picking different lengths and widths, just as long as (length+width)=5.