59.25 seconds
After 1 half-life: 16*(1/2) = 8 g remains
After 2 half-lives: 8*(1/2) = 4g remains
After 3 half-lvies: 4*(1/2) = 2g remains
After 4 half-lives: 2*(1/2) = 1g remains
So after 4 half-lves you have 1 gram of Na25 left. This is also the amount remaining after 237 seconds. Since 4 half-lives have elapsed over 237 seconds, you can divide 237 seconds by 4 to find the half-life of Na25 is 59.25 seconds.
You can also figure it out using the rate of decay formula:
At = Ao*e-kt
where Ao is the initial amount, At is the amount left after some time t. k is the decay constant which is k = ln 2 / t1/2 where t1/2 is the half-life.
In this case Ao = 16g, At = 1g, t=237 sec
Substitute in the formula to solve for k, then take the answer for k and use it in the other formula to solve for the half-life (t1/2):
1 = 16*e-237k
ln (1/16) = ln (e-237k)
-2.7726 = -237k
k = -2.7726/-237 = 0.011699 sec-1
t1/2 = ln 2/k = 0.693147/0.011699 sec-1
t1/2 = 59.25 sec
To determine the percentage of As-81 that remains undecayed after 43.2 seconds, you would need to know its half-life. As-81 has a half-life of approximately 46.2 seconds. Using the formula for radioactive decay, after one half-life (46.2 seconds), 50% would remain. Since 43.2 seconds is slightly less than one half-life, a little more than 50% of the sample remains undecayed, but the exact percentage requires calculations based on the exponential decay formula.
As the sample size increases, the standard deviation of the sample mean, also known as the standard error, tends to decrease. This is because larger samples provide more accurate estimates of the population mean, leading to less variability in sample means. However, the standard deviation of the population itself remains unchanged regardless of sample size. Ultimately, a larger sample size results in more reliable statistical inferences.
The half-life of sodium-25 can be determined by the decay of the sample. If 1.00 gram remains from an initial 16.00-gram sample, then 15.00 grams have decayed. This means that 1.00 gram represents ( \frac{1}{16} ) of the original sample, which indicates that the sample has gone through four half-lives (since ( \frac{1}{2^4} = \frac{1}{16} )). Therefore, if the time taken for these four half-lives is known, the half-life can be calculated as one-fourth of that total time.
To determine the percent of As-81 that remains un-decayed after 43.3 seconds, you would need to know its half-life. The half-life of As-81 is approximately 46.2 seconds. Given that 43.3 seconds is slightly less than one half-life, you can use the formula for exponential decay: [ N(t) = N_0 \left( \frac{1}{2} \right)^{t/T_{1/2}} ] where ( N_0 ) is the initial quantity, ( t ) is the elapsed time, and ( T_{1/2} ) is the half-life. After 43.3 seconds, about 80% of the original sample of As-81 would remain un-decayed.
To determine the remaining amount of a 200 gram sample after 36 seconds with a half-life of 12 seconds, we first calculate how many half-lives fit into 36 seconds. There are three half-lives in 36 seconds (36 ÷ 12 = 3). Each half-life reduces the sample by half: after the first half-life, 100 grams remain; after the second, 50 grams; and after the third, 25 grams. Therefore, 25 grams of the sample would remain after 36 seconds.
2
Nitrogen-16 has a half-life of about 7.13 seconds. After 36.0 seconds, there would be 3 half-lives. Therefore, 1/2 * 1/2 * 1/2 = 1/8 of the original sample remains unchanged.
1.5% remains after 43.2 seconds.
After 2 half lives, 25% of the original radioactive sample remains unchanged. This is because half of the sample decays in each half life, so after 1 half life, 50% has decayed, and after 2 half lives, another 50% has decayed, leaving 25% unchanged.
After 1.6 seconds, 0.6 g astatine-218 remains unchanged. This amount is reduced by half to 0.3 g at 3.2 seconds. It is halved again at 4.8 seconds to 0.15 g, and halved once more to 0.075 g unchanged after a total of 6.4 seconds.
Density is an intensive quantity which means it is independent of size. This can be seen from the definition of density. Density = mass/volume So if the sample size increases than so does the mass, but the density remains unchanged.
halflife
This would depend on the specific sample and its stability. Without additional information, it is not possible to determine how much of the sample would remain unchanged after two hours.
Thorium-234 has a half-life of 24.1 days. How much of a 100-g sample of thorium-234 will be unchanged after 48.2 days?
After 48,2 days the amount of Th-234 will be 25 g.
After 3 half-lives, half of the original sample would remain unchanged. After the 1st half-life: 300 unchanged atoms. After the 2nd half-life: 150 unchanged atoms. After the 3rd half-life: 75 unchanged atoms would remain.
Three half lives have elapsed. This can be determined by calculating how many times the original sample size must be halved to get to one eighth: (1/2) * (1/2) * (1/2) = 1/8.