59.25 seconds
After 1 half-life: 16*(1/2) = 8 g remains
After 2 half-lives: 8*(1/2) = 4g remains
After 3 half-lvies: 4*(1/2) = 2g remains
After 4 half-lives: 2*(1/2) = 1g remains
So after 4 half-lves you have 1 gram of Na25 left. This is also the amount remaining after 237 seconds. Since 4 half-lives have elapsed over 237 seconds, you can divide 237 seconds by 4 to find the half-life of Na25 is 59.25 seconds.
You can also figure it out using the rate of decay formula:
At = Ao*e-kt
where Ao is the initial amount, At is the amount left after some time t. k is the decay constant which is k = ln 2 / t1/2 where t1/2 is the half-life.
In this case Ao = 16g, At = 1g, t=237 sec
Substitute in the formula to solve for k, then take the answer for k and use it in the other formula to solve for the half-life (t1/2):
1 = 16*e-237k
ln (1/16) = ln (e-237k)
-2.7726 = -237k
k = -2.7726/-237 = 0.011699 sec-1
t1/2 = ln 2/k = 0.693147/0.011699 sec-1
t1/2 = 59.25 sec
True
The answer depends on 3240 WHAT: seconds, days, years?
a sample is a sample sized piece given... a sample size is the amount given in one sample
An experimental sample is an experiment that is just a sample of what you are looking for.
sample is a noun and sampling is TO sample(verb)
2
Nitrogen-16 has a half-life of about 7.13 seconds. After 36.0 seconds, there would be 3 half-lives. Therefore, 1/2 * 1/2 * 1/2 = 1/8 of the original sample remains unchanged.
After 2 half lives, 25% of the original radioactive sample remains unchanged. This is because half of the sample decays in each half life, so after 1 half life, 50% has decayed, and after 2 half lives, another 50% has decayed, leaving 25% unchanged.
1.5% remains after 43.2 seconds.
After 6.4 seconds, there would be 0.3g of the original sample of Astatine-218 remaining unchanged. This is calculated by dividing the time elapsed by the half-life to determine the number of half-lives passed (6.4 s ÷ 1.6 s = 4 half-lives), then using this to calculate the remaining amount (1.2 g ÷ 2^4 = 0.3 g).
Density is an intensive quantity which means it is independent of size. This can be seen from the definition of density. Density = mass/volume So if the sample size increases than so does the mass, but the density remains unchanged.
halflife
This would depend on the specific sample and its stability. Without additional information, it is not possible to determine how much of the sample would remain unchanged after two hours.
After 48.2 days (two half-lives), one-fourth (25%) of the original thorium-234 sample will remain unchanged. Therefore, 25 g of the 100-g sample will be unchanged after 48.2 days.
Thorium-234 has a half-life of 24.1 days. After 48.2 days, half of the sample will remain unchanged. Therefore, 50% of the original 100 g sample, which is 50 g, will be unchanged after 48.2 days.
After 3 half-lives, half of the original sample would remain unchanged. After the 1st half-life: 300 unchanged atoms. After the 2nd half-life: 150 unchanged atoms. After the 3rd half-life: 75 unchanged atoms would remain.
Three half lives have elapsed. This can be determined by calculating how many times the original sample size must be halved to get to one eighth: (1/2) * (1/2) * (1/2) = 1/8.