Q: What is the height of a flag pole that cast a shadow of 7.42 m at an angle of elevation 48.4 degrees on level ground?

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18.6 m/52.6 degrees tan= 14.2

By means of trigonometry if you know the angle of elevation or by comparing it with a nearby object if you know its height and shadow length.

A pole casting a shadow 49 feet long with an angle of elevation of the sun of 44.8 degrees is 50 feet tall. (47.98 rounded to two places)Tangent (theta) = opposite / adjacentTangent (44.9) = X / 49X = 47.98This does not take into account the curvature of the earth, but the error in this example is inconsequential, specifically an elevation error of about 0.015 percent.

In addition to the height of the object, the length of its shadow depends on a few other things that are not described in the question. -- Is the object standing straight upright ? -- Is the shadow cast on the ground or on sometheing else? -- If on the ground, is the ground level ? -- What is the altitude (angle) of the sun ?

Using trigonometry the angle of elevation is 77 degrees rounded to the nearest degree

Related questions

When the angle of elevation equals 45 degrees. tan-1(1) = 45 degrees.

(Height of the building)/(length of the shadow) = tangent of 31Ã‚Â° .Height = 73 tan(31Ã‚Â°) = 43.9 feet (rounded)

The flagpole is 15.92 metres, approx.

51.34019175 degrees or as 51o20'24.69''

You can use trigonometry to find the angle of elevation. Let x be the distance from the tip of the shadow to the base of the pole and the height of the pole be y. Then, tan(60 degrees) = y/x. Given that the height of the pole is 12 feet, you can solve for x to find the angle of elevation.

Angle of elevation: tan-1(100/130) = 37.6 degrees rounded to one decimal place

18.6 m/52.6 degrees tan= 14.2

If you also know its shadow then you can work out the angle of elevation

By means of trigonometry if you know the angle of elevation or by comparing it with a nearby object if you know its height and shadow length.

Using trigonometery if you know the length of its shadow and angle of elevation

Using the tangent ratio height of telegraph pole is 55 feet to the nearest integer.

It is: tan(52)*9 = 11.519 meters rounded to three decimal places