All rotations, other than those of 180 degrees should be further qualified as being clockwise or counter-clockwise. This one is not and I am assuming that the direction of rotation is the same as measurement of polar angles. Also, a rotation is not properly defined unless the centre of rotation is specified. I am assuming that the centre of rotation is the origin. Without these two assumptions any point in the plane can be the image. With the assumptions, for which there is no valid reason, the image is (3, -4).
The answer depends on the centre of rotation. A rotation cannot be described without specifying the centre of rotation.
The 3 transformations of math are: translation, reflection and rotation. These are the well known ones. There is a fourth, dilation, in which the pre image is the same shape as the image, but the same size in the world
30 is one sixth of 180. As a percentage, this is 16.6 recurring percent. This can be represented on paper as 16.6%, with the 6 after the decimal point having a dot on the top.
Consider an irregular polygon with an even number of sides - 2n. If the sides 1 and n+1 are of the same length, sides 2 and n+2, sides 3 and n + 3 etc and if the corresponding angles are the same, then the polygon will have a rotational symmetry of 180 degrees.
What is the image of point (3, 5) if the rotation is
If the point (3,5) is rotated 180 degrees, it becomes (-3,-5).
If the point (3,5) is rotated 180 degrees, it becomes (-3,-5).
(-4,-3) anything with a 180 degree rotation regardless of being postive or negative is always negative the numbers in parenthesis.
The rule for a rotation by 180° about the origin is (x,y)→(−x,−y) .
Conventionally positive angles are measured anticlockwise, by 180° is a half turn regardless of direction. It depends where the centre of rotation is, so where would you like the image to be? If the centre is at, say, (4, 3) then the image will be at (4, 3) regardless of the angle of rotation. If the centre is at, say, (4, 4) then the image will be at (4, 5) If the centre is at, say, the origin, ie (0, 0) then the image will be at (-4, -3).
The image is (-5, 3)
It is: (-4, -3)
It then is: (-3, -5)
It is: (-4, -3)
All rotations, other than those of 180 degrees should be further qualified as being clockwise or counter-clockwise. This one is not and I am assuming that the direction of rotation is the same as measurement of polar angles. Also, a rotation is not properly defined unless the centre of rotation is specified. I am assuming that the centre of rotation is the origin. Without these two assumptions any point in the plane can be the image. With the assumptions, for which there is no valid reason, the image is (3, -4).
(-5,3)