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Integral of x dx / sqrt(x+2)
Make the substitution sqrt(x+2)=u
(x+2)^(1/2) = u
(1/2)(x+2)^(-1/2) dx = du
1/2(x+2)^(1/2) dx = du
1/2sqrt(x+2) dx = du
1/sqrt(x+2) dx = 2 du
Integral of x dx / sqrt(x+2) = Integral 2 x du
sqrt(x+2) = u
(x+2)=u^2
x=u^2-2
Integral 2 x du = Integral 2(u^2-2) du
= Integral 2u^2 du - 4 du
= 2 u^3/3 - 4u + C
= (2/3) (x+2)^(3/2) - 4 sqrt(x+2) + C
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What is sqrt3 plus sqrt2 divided by sqrt 6?
[The sqrt(3)+sqrt(2)]/sqrt(6)can be solved by multiply the numerator and denominator by sqrt(6)This gives sqrt(18)+sqrt(12)/6This can be simplified to[3(sqrt(2)+2(sqrt(3)]/6
What is 5 plus the square root of 5 divided by 2?
(5 + sqrt(5)) / 2 = 3.61803399
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3
How do you rationalize the denominator in this expression the square root of x minus 2 divided by the square root of x plus 2?
4
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x*sqrt(2)/{5 - sqrt(3)} = {5 + sqrt(3)} => x*sqrt(2) = {5 + sqrt(3)} * {5 - sqrt(3)} = 25 - 3 = 22 => x = 22/sqrt(2) = 22*sqrt(2)/{sqrt(2)*sqrt(2)} = 22*sqrt(2)/2 = 11*sqrt(2)
What is sqrt3 plus sqrt2 divided by sqrt 6?
[The sqrt(3)+sqrt(2)]/sqrt(6)can be solved by multiply the numerator and denominator by sqrt(6)This gives sqrt(18)+sqrt(12)/6This can be simplified to[3(sqrt(2)+2(sqrt(3)]/6
What is 5 plus the square root of 5 divided by 2?
(5 + sqrt(5)) / 2 = 3.61803399
How do you integrate the integral of quantity of x plus 2 divided by x squared plus x plus 1?
3
How do you rationalize the denominator in this expression the square root of x minus 2 divided by the square root of x plus 2?
4
How do you find the value of x if x root 2 divided by 5 minus root 3 equals 5 plus root 3?
x*sqrt(2)/{5 - sqrt(3)} = {5 + sqrt(3)} => x*sqrt(2) = {5 + sqrt(3)} * {5 - sqrt(3)} = 25 - 3 = 22 => x = 22/sqrt(2) = 22*sqrt(2)/{sqrt(2)*sqrt(2)} = 22*sqrt(2)/2 = 11*sqrt(2)
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No
RMS of non sinusoidal?
Vrms=sqrt[1/T * integral(v^2(t)dt, 0,t] Irms=sqrt[1/T * integral(i^2(t)dt, 0,t]
What is the square root of eight divided by 2 square root of three?
sqrt(8)/[2*sqrt(3)] = 2*sqrt(2)/[2*sqrt(3)] = sqrt(2)/sqrt(3) = sqrt(2/3)
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Approximately 2.828427
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0.2857
