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Integral of x dx / sqrt(x+2)

Make the substitution sqrt(x+2)=u

(x+2)^(1/2) = u

(1/2)(x+2)^(-1/2) dx = du

1/2(x+2)^(1/2) dx = du

1/2sqrt(x+2) dx = du

1/sqrt(x+2) dx = 2 du

Integral of x dx / sqrt(x+2) = Integral 2 x du

sqrt(x+2) = u

(x+2)=u^2

x=u^2-2

Integral 2 x du = Integral 2(u^2-2) du

= Integral 2u^2 du - 4 du

= 2 u^3/3 - 4u + C

= (2/3) (x+2)^(3/2) - 4 sqrt(x+2) + C

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Q: What is the integral of x divided by sq-rt of x plus 2?
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