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62. One less than the divisor.

Q: What is the largest remainder possible if the divisor is 63?

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62

To determine the remainder when dividing 63 by a divisor, you need to perform the division and look at the remainder. For example, if you divide 63 by 5, the remainder is 3. However, if you divide it by 7, the remainder is 0.

Then divide the remainder again by the divisor until you get a remainder smaller than your divisor or an remainder equal to zero. The remainder in a division question should never be larger than the "divisor", but the remainder often is larger than the "answer" (quotient). For example, if 435 is divided by 63, the quotient is 22 and the remainder is 57.

7

76.1111

Related questions

62

The greatest integer remainder for a division sum with a divisor of 63 would be 62 - for a number one fewer than an integer multiple of 63 - for example, 125/63 = 1 remainder 62.

To determine the remainder when dividing 63 by a divisor, you need to perform the division and look at the remainder. For example, if you divide 63 by 5, the remainder is 3. However, if you divide it by 7, the remainder is 0.

Then divide the remainder again by the divisor until you get a remainder smaller than your divisor or an remainder equal to zero. The remainder in a division question should never be larger than the "divisor", but the remainder often is larger than the "answer" (quotient). For example, if 435 is divided by 63, the quotient is 22 and the remainder is 57.

To find the largest number that, when divided into both 63 and 75, leaves a remainder of three, you can use the concept of greatest common divisor (GCD) or greatest common factor (GCF). The GCD of 63 and 75 is the largest number that can evenly divide both numbers. To find it, you can use the Euclidean algorithm: Start with the two numbers: 63 and 75. Divide 75 by 63: 75 ÷ 63 = 1 with a remainder of 12. Now, replace the larger number (75) with the remainder (12) and keep the smaller number (63) as is: 63 and 12. Repeat the process: 63 ÷ 12 = 5 with a remainder of 3. Again, replace the larger number (63) with the remainder (3) and keep the smaller number (12) as is: 12 and 3. Repeat once more: 12 ÷ 3 = 4 with no remainder. Now that you have reached a point where the remainder is 0, the GCD is the last non-zero remainder, which is 3. So, the largest number that, when divided into both 63 and 75, leaves a remainder of three is 3.

Why not use the Euclidean Algorithm and find out? Divide 63 by 25, and you get a remainder of 13. (The quotient is not important.) Now the divisor of the last division problem becomes the dividend, and the remainder becomes the divisor - that is, we divide 25 by 13 this time. We get a remainder of 12. Divide 13 by 12, and you get a remainder of 1. Divide 12 by 1, you get no remainder. Therefore, this last divisor, 1, is the greatest common factor (or divisor) of the original two numbers. (As a side note, because the gcf is 1, that means those two numbers are what's called relatively prime.)

The Greatest Common Divisor of 35, 63 is 7.

7

0.0635

76.1111

7.875

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