It is not possible to answer the question because there is insufficient information. Also, there is no way of telling whether the trapezoid has AB parallel to DC (with AD and BC equal) or if AD is parallel to CB (with AB and DC equal). It is not clear what is meant by ccd. What is x? In any case, the length of one side, whichever it is, is not enough to answer the question.
10/3
cm (centimeter) is a unit of length. I don't recognize dc as a unit of length, so most likely you can't convert it.
58 years are between 30 BC and AD 30. The first thing you need to remember is that there is no year 0; the year before AD 1 is 1 BC. So the years between 30 BC and AD 30 are... 29 BC, 28 BC, 27 BC, ..., 2 BC, 1 BC, AD1, AD 2, ..., AD 27, AD 28, AD 29 29 BC through 1 BC is 29 years, and AD 1 through AD 29 is 29 years. 29 years + 29 years = 58 years
The circumference of a circle with a diameter of 30 units of length is pi*30 = 94.2 units. The circumference of a circle with a diameter of 30 units of length is pi*30 = 94.2 units. The circumference of a circle with a diameter of 30 units of length is pi*30 = 94.2 units. The circumference of a circle with a diameter of 30 units of length is pi*30 = 94.2 units.
poopy brain blah blah
let abc be the triangle with base bc. Consider it is equilateral triangle.. Now draw ad perpendicular to bc. Now ad equalls dc. Now tan 60 degree equalls ad/dc. With value of tan 60 and ad we can find dc. There fore bc equalls 2 * dc
It is not possible to answer the question because there is insufficient information. Also, there is no way of telling whether the trapezoid has AB parallel to DC (with AD and BC equal) or if AD is parallel to CB (with AB and DC equal). It is not clear what is meant by ccd. What is x? In any case, the length of one side, whichever it is, is not enough to answer the question.
a/b=c/d =>ad=bc =>a =bc/d b =ad/c c =ad/b d =bc/a so if a+b=c+d is true => (bc/d)+(ad/c)=(ad/b)+(bc/a) => (bc2+ad2)/dc=(da2+cb2)/ab => ab(bc2+ad2)=dc(da2+cb2) and since ad=bc, => ab(adc+add) =dc(ada+adc) => abadc+abadd =dcada + dcadc => abadc-dcadc =dcada-abadd => (ab-dc)adc =(dc-ab)add ad cancels out => (ab-dc)c =(dc-ab)d => -(dc-ab)c =(dc-ab)d => -c = d so there's your answer :)
Given that AB = 8 units and AD = 10 units, we can use the ratios of corresponding sides in similar triangles to find the measure of DC. Since triangle ADC is similar to triangle ABC, the ratio of DC to AB is equal to the ratio of AD to AC. Thus, DC/8 = 10/AC. Solving for DC, DC = 8 * 10 / AC.
10/3
10/3
cm (centimeter) is a unit of length. I don't recognize dc as a unit of length, so most likely you can't convert it.
58 years are between 30 BC and AD 30. The first thing you need to remember is that there is no year 0; the year before AD 1 is 1 BC. So the years between 30 BC and AD 30 are... 29 BC, 28 BC, 27 BC, ..., 2 BC, 1 BC, AD1, AD 2, ..., AD 27, AD 28, AD 29 29 BC through 1 BC is 29 years, and AD 1 through AD 29 is 29 years. 29 years + 29 years = 58 years
1968 = AD
It is the scale factor times the length of ad.
There is no such length unit abbreviation as dc - perhaps you are thinking of dm, which stands for decimetre.