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To determine the length of side BD in a triangle, we need more information about the triangle, such as the lengths of the other sides, the angles, or any specific relationships between the sides. If you have a specific triangle in mind (like a right triangle) or additional context (like if BD and DC are parts of a segment), please provide that information for a more accurate answer. Without that, we can't calculate the length of side BD solely based on the length of side DC.
What else can I help you with?
Have a rectangle bdfg with point a on side bd so that ba equals 16 cm and ad equals 8 cm what fraction of the area of the rectangle is inside triangle baf?
ba=(16/(16+8))bd=(16/24)bd=(2/3)bd area of the rectangle = bd*bf area of triangle = (2/3)bd*bf/2=(1/3)*bd*bf 1/3
What is the length of side bd?
To determine the length of side BD, additional information such as the shape, dimensions, or relationships between the sides is required. If BD is part of a geometric figure, please provide details like coordinates, angles, or other relevant measurements. Without this context, it's impossible to give a specific answer.
what- triangle ACE?
BD= AF
If the median to a side of a triangle is also an altitude to that side then the triangle is isosceles How do you write this Proof?
Let the triangle be ABC and suppose the median AD is also an altitude.AD is a median, therefore BD = CDAD is an altitude, therefore angle ADB = angle ADC = 90 degreesThen, in triangles ABD and ACD,AD is common,angle ADB = angle ADCand BD = CDTherefore the two triangles are congruent (SAS).And therefore AB = AC, that is, the triangle is isosceles.
How do you solve this geometry proof?
Given ABE, ADC, BD bisescts angle ABC and BD is parallel to EC prove: Triangle EBC is isoceles
What is the length of a hair?
the normal length of a hair would be 18-20 cm :P :) BD
Have a rectangle bdfg with point a on side bd so that ba equals 16 cm and ad equals 8 cm what fraction of the area of the rectangle is inside triangle baf?
ba=(16/(16+8))bd=(16/24)bd=(2/3)bd area of the rectangle = bd*bf area of triangle = (2/3)bd*bf/2=(1/3)*bd*bf 1/3
In rhombus ABCD BD 18 AC 24 What is the length of each side?
84
what- triangle ACE?
BD= AF
In rhombus abcd bd equals 18 ac equals 24 what is the length of each side?
15 units
In rhombus abcd bd equals 6 and ac equals 8 what is the length of each side?
5 units
If the median to a side of a triangle is also an altitude to that side then the triangle is isosceles How do you write this Proof?
Let the triangle be ABC and suppose the median AD is also an altitude.AD is a median, therefore BD = CDAD is an altitude, therefore angle ADB = angle ADC = 90 degreesThen, in triangles ABD and ACD,AD is common,angle ADB = angle ADCand BD = CDTherefore the two triangles are congruent (SAS).And therefore AB = AC, that is, the triangle is isosceles.
If d is the midpoint of ac and c is the midpoint of bd what is the length of ab if bd is 12cm?
16cm
What is the area of rhombus ABCD if AC equals 12 and BD equals 7?
The 2 lengths that you described are diagonals. The area of a rhombus when you know the diagonals is half the product of the diagonals:Area = (1/2) * ( 12 * 7) = 42.The way this works: for a rhombus, the diagonals bisect each other (they intersect at the other's midpoint), so split this into two identical triangles BCD and BAD.The area of one of these triangles is (1/2) * Base * Height, with Base = length of BD, and Height = 1/2 length of AC.So area of one triangle = (1/2) * BD * ((1/2)*AC), and area of rhombus is 2 * area of triangle, so you have 2 * (1/2) * BD * ((1/2)*AC) = (1/2) * (BD) * (AC)
How do you solve this geometry proof?
Given ABE, ADC, BD bisescts angle ABC and BD is parallel to EC prove: Triangle EBC is isoceles
If triangle AC equals 6 and BD equals 4 find AB?
If AC equals 6 and BD equals 4, then AB equals 5.
How many layers of data can be stored on one side of a BD-ROM?
2 layers but up to 20 layers are expected in the near future
