Points: (2, 3) and (5, 7)
Length of line: 5
Slope: 4/3
Perpendicular slope: -3/4
Midpoint: (3.5, 5)
Bisector equation: 4y = -3x+30.5 or as 3x+4y-30.5 = 0
Points: (2, 3) and (5, 7)Length: 5 unitsSlope: 4/3Perpendicular slope: -3/4Midpoint: (3.5, 5)Equation: 3y = 4x+1Bisector equation: 4y = -3x+30.5
An isosceles triangle will always have a perpendicular bisector that is also an angle bisector. In an isosceles triangle, the two sides are of equal length, and the perpendicular bisector of the base (the unequal side) also divides the vertex angle into two equal angles, thus serving as an angle bisector as well.
The distance will be length of the line divided by 2 because the perpendicular bisector cuts through the line at its centre and at right angles
The mid-point is needed when the perpendicular bisector equation of a straight line is required. The distance formula is used when the length of a line is required.
4x + 3y = 24 crosses the axes at (6, 0) and (0, 8). Therefore its length is [(6 - 0)2 + (0 - 8)2]1/2 = [36 + 64]1/2 = 1001/2 = 10 Mid point = (3, 4) Gradient of given line = -4/3 So gradient of perpendicular bisector = 3/4 Therefore equation of perp bisector: (y - 4) = 3/4(x - 3) or 4y - 16 = 3x - 9 3x - 4y = -7
Points: (2, 3) and (5, 7)Length: 5 unitsSlope: 4/3Perpendicular slope: -3/4Midpoint: (3.5, 5)Equation: 3y = 4x+1Bisector equation: 4y = -3x+30.5
An isosceles triangle will always have a perpendicular bisector that is also an angle bisector. In an isosceles triangle, the two sides are of equal length, and the perpendicular bisector of the base (the unequal side) also divides the vertex angle into two equal angles, thus serving as an angle bisector as well.
The distance will be length of the line divided by 2 because the perpendicular bisector cuts through the line at its centre and at right angles
The mid-point is needed when the perpendicular bisector equation of a straight line is required. The distance formula is used when the length of a line is required.
So that the arc is mid-way in perpendicular to the line segment
Because both lines and rays are infinite in length and thus have no midpoint.
4x + 3y = 24 crosses the axes at (6, 0) and (0, 8). Therefore its length is [(6 - 0)2 + (0 - 8)2]1/2 = [36 + 64]1/2 = 1001/2 = 10 Mid point = (3, 4) Gradient of given line = -4/3 So gradient of perpendicular bisector = 3/4 Therefore equation of perp bisector: (y - 4) = 3/4(x - 3) or 4y - 16 = 3x - 9 3x - 4y = -7
Every point on the bisector of an angle is equidistant from the sides of that angle. It is understood that the distance of a point from a line is the length of the perpendicular dropped from the point to the line.
A segment has exactly one bisector. This bisector is a line (or line segment) that divides the original segment into two equal parts and is perpendicular to it. No matter the length of the segment, the unique bisector will always pass through the midpoint of the segment.
Points: (7, 5) Equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Equations intersect at: (4, 1) Length of perpendicular line: 5
Points: (2, 3) and (5, 7)Midpoint: (2+5)/2 and (3+7)/2 = (3.5, 5)Length: square root of (2-5)2+(3-7)2 = 5Slope: (3-7)/(2-5) = 4/3Perpendicular slope: -3/4Equation: y-3 = 4/3(x-2) => 3y = 4x+1Perpendicular equation: y-5 = -3/4(x-3.5) => 4y = -3x+30.5
1 Point of origin: (7, 5) 2 Equation: 3x+4y-16 = 0 3 Perpendicular equation: 4x-3y-13 = 0 4 Both equations intersect at: (4, 1) 5 Line length is the square root of: (7-4)2+(5-1)2 = 5