4x + 3y = 24 crosses the axes at (6, 0) and (0, 8).
Therefore its length is [(6 - 0)2 + (0 - 8)2]1/2 = [36 + 64]1/2 = 1001/2 = 10
Mid point = (3, 4)
Gradient of given line = -4/3
So gradient of perpendicular bisector = 3/4
Therefore equation of perp bisector: (y - 4) = 3/4(x - 3)
or 4y - 16 = 3x - 9
3x - 4y = -7
Points: (2, 3) and (5, 7) Length of line: 5 Slope: 4/3 Perpendicular slope: -3/4 Midpoint: (3.5, 5) Bisector equation: 4y = -3x+30.5 or as 3x+4y-30.5 = 0
The distance will be length of the line divided by 2 because the perpendicular bisector cuts through the line at its centre and at right angles
The mid-point is needed when the perpendicular bisector equation of a straight line is required. The distance formula is used when the length of a line is required.
Points: (2, 3) and (5, 7)Length: 5 unitsSlope: 4/3Perpendicular slope: -3/4Midpoint: (3.5, 5)Equation: 3y = 4x+1Bisector equation: 4y = -3x+30.5
Every point on the bisector of an angle is equidistant from the sides of that angle. It is understood that the distance of a point from a line is the length of the perpendicular dropped from the point to the line.
Points: (2, 3) and (5, 7) Length of line: 5 Slope: 4/3 Perpendicular slope: -3/4 Midpoint: (3.5, 5) Bisector equation: 4y = -3x+30.5 or as 3x+4y-30.5 = 0
The distance will be length of the line divided by 2 because the perpendicular bisector cuts through the line at its centre and at right angles
The mid-point is needed when the perpendicular bisector equation of a straight line is required. The distance formula is used when the length of a line is required.
So that the arc is mid-way in perpendicular to the line segment
Because both lines and rays are infinite in length and thus have no midpoint.
Points: (2, 3) and (5, 7)Length: 5 unitsSlope: 4/3Perpendicular slope: -3/4Midpoint: (3.5, 5)Equation: 3y = 4x+1Bisector equation: 4y = -3x+30.5
Every point on the bisector of an angle is equidistant from the sides of that angle. It is understood that the distance of a point from a line is the length of the perpendicular dropped from the point to the line.
Points: (7, 5) Equation: 3x+4y-16 = 0 Perpendicular equation: 4x-3y-13 = 0 Equations intersect at: (4, 1) Length of perpendicular line: 5
Straight line equation: y = 2x+10 Perpendicular equation: y = -1/2x+5 They intersect at: (-2, 6) Length of perpendicular2: (2--2)2+(4-6)2 = 20 and the square root of this is 4.472135955 Therefore distance is 4.472135955 units in length
The equation to find the volume of a rectangular object is (a) volume equals length times width times height.
1 Point of origin: (7, 5) 2 Equation: 3x+4y-16 = 0 3 Perpendicular equation: 4x-3y-13 = 0 4 Both equations intersect at: (4, 1) 5 Line length is the square root of: (7-4)2+(5-1)2 = 5
No. A line of any length can be divided in half - and that is what a bisector is.