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The length of a rectangle is three times its width If the perimeter of the rectangle is 48 inches what is its area?
Width = 'W'. Length = '3W'. Perimeter = 2 (Length + W) = 2 (3W + W) = 2 (4W) = 8W = 48 W = 6 inches and Length = 18inches Area = (Length) x W = 108 sq in============================ Easier way: Width = W, Length = 3W Area = (W) x (3W) = 3W2 We showed above that W = 6 3W2 = 3 x 36 = 108 in2
How many widths equal one length?
If the length is L units and the width is W units then L/W widths equal one length.
If a rectangle is 220 all around and the length is 6 then what is the width?
A rectangle with length L and width W has perimeter = 2*(L+W) So, 2(6 + W) = 220 or 6 + W = 110 so that W = 104 Usually, Length > Width but clearly not in this case.
The length of the rectangle is greater than its breadth by 2 cm if the length is increased by 4 cm and the breadth decreased by 3cm the area remain same find the length and breadth of the rectangle?
The width is 18 cm and the length is 20 cm. The new dimensions are 15 by 24. The formula used is if w=width, w (w + 2) = (w - 3) (w + 6).
What is the area of a rectangle that has and area of 30 centimeters and the length is twice the width?
you know that: Area=length x width Area=A=30 cm2 and that the width= w and that the length= 2w so, what you do is: 30=2w*w (solve for w) 30=2w2 15=w2 take the square root of 15=w w=3.87cm Your width is 3.87cm your length is 2(3.87)=7.75cm
If the area of a rectangle is 40 square inches and the length is 6 inches more than the width what is the length and the width of the rectangle?
(6 + w) = length w = width (6 + w)(w) = 40 square inches w squared + 6w = 40 w = 4 inches and the length must be equal to 10 inches
The length of a rectangle is three times its width If the perimeter of the rectangle is 48 inches what is its area?
Width = 'W'. Length = '3W'. Perimeter = 2 (Length + W) = 2 (3W + W) = 2 (4W) = 8W = 48 W = 6 inches and Length = 18inches Area = (Length) x W = 108 sq in============================ Easier way: Width = W, Length = 3W Area = (W) x (3W) = 3W2 We showed above that W = 6 3W2 = 3 x 36 = 108 in2
The length of a rectangle is 6 inches more than its width The perimeter of the rectangle is 24 inches What is the length of the rectangle?
P of rectangle = 2(L+W) where L=W+6 24 = 2(W+(W+6)) 12 = W+ W+ 6 6 = 2 W 3 = W The length (W+6) is 9, width (W) is 3.
How many widths equal one length?
If the length is L units and the width is W units then L/W widths equal one length.
If a rectangle is 220 all around and the length is 6 then what is the width?
A rectangle with length L and width W has perimeter = 2*(L+W) So, 2(6 + W) = 220 or 6 + W = 110 so that W = 104 Usually, Length > Width but clearly not in this case.
How do you find the length given area and width?
Length (L) equals area (A) divided by width (W); or L = A / W.
The length of the rectangle is greater than its breadth by 2 cm if the length is increased by 4 cm and the breadth decreased by 3cm the area remain same find the length and breadth of the rectangle?
The width is 18 cm and the length is 20 cm. The new dimensions are 15 by 24. The formula used is if w=width, w (w + 2) = (w - 3) (w + 6).
What is the area of a rectangle that has and area of 30 centimeters and the length is twice the width?
you know that: Area=length x width Area=A=30 cm2 and that the width= w and that the length= 2w so, what you do is: 30=2w*w (solve for w) 30=2w2 15=w2 take the square root of 15=w w=3.87cm Your width is 3.87cm your length is 2(3.87)=7.75cm
The length of the top of a table is 2m greater than the width The area is 80m2 What is the width?
8m Let the width of the table be w; then its length is w + 2. Area = length x width 80 = (w + 2)w w2 + 2w - 80 = 0 (w + 10)(w - 8) = 0 w = -10 or 8 As the width must be positive, it is 8m.
What is an expression for the perimeter of a rectangle that has a length which is seven times its width?
Perimeter = length + length + width + width Let "w" = width, then "7w" must equal the length (because it's 7 times the width) 7w + 7w + w + w = perimeter 16w = perimeter
If perimeter is 96 and if the length is 27 more than the width what is the length?
Perimeter is twice the length and width added together. 48=l+w l=w+27 48=w+27+w 48=2w+27 48-27=2w 21=2w 10.5=w 37.5=l **********
The length of a rectangle is 2 meters more than its width The area of the rectangle is 80 square meters What is the length and width of the rectangle?
if width is equal to W and length is equal to L, then W x L = 80 L = W +2 so W x (W+2) = 80 solve to find W=8 and L= 10
