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The length of a rectangle is three times its width If the perimeter of the rectangle is 48 inches what is its area?
Width = 'W'. Length = '3W'. Perimeter = 2 (Length + W) = 2 (3W + W) = 2 (4W) = 8W = 48 W = 6 inches and Length = 18inches Area = (Length) x W = 108 sq in============================ Easier way: Width = W, Length = 3W Area = (W) x (3W) = 3W2 We showed above that W = 6 3W2 = 3 x 36 = 108 in2
How many widths equal one length?
If the length is L units and the width is W units then L/W widths equal one length.
If a rectangle is 220 all around and the length is 6 then what is the width?
A rectangle with length L and width W has perimeter = 2*(L+W) So, 2(6 + W) = 220 or 6 + W = 110 so that W = 104 Usually, Length > Width but clearly not in this case.
The length of the rectangle is greater than its breadth by 2 cm if the length is increased by 4 cm and the breadth decreased by 3cm the area remain same find the length and breadth of the rectangle?
The width is 18 cm and the length is 20 cm. The new dimensions are 15 by 24. The formula used is if w=width, w (w + 2) = (w - 3) (w + 6).
What is the area of a rectangle that has and area of 30 centimeters and the length is twice the width?
you know that: Area=length x width Area=A=30 cm2 and that the width= w and that the length= 2w so, what you do is: 30=2w*w (solve for w) 30=2w2 15=w2 take the square root of 15=w w=3.87cm Your width is 3.87cm your length is 2(3.87)=7.75cm
