255
-127 or -128
There are 8 bits in a byte, so a two byte integer would be 16 bits. The largest 16 bit integer possible would be 11111111111111112, which is 65535 in base 10.
2.0
byte has 8 bits all bits at 0 = zero all bits at 1 = 255
11111111; 255 or 1+2+4+8+16+32+64+128=255 Answer 255 There are 8 bits in a byte when all are set to zero (turned off) then the value is 0. When all of the bits in a byte are set to 1 (turned on) you get the largest value that a byte holds which is 255.
The address of the last byte in a 512 mega byte memory, expressed as a decimal number, is 536,870,911.
-127 or -128
255 is the largest decimal number. 1 byte (8 bits) can store 256 *values* (0-255).
The biggest number that can be represented in one byte is 11111111. Binary numbers have the ability to added together in a fashion similar to decimal numbers.
0.00195 KB equals 2 bytes
BCD:A byte (unpacked) representation of a decimal digit in the range0 through9. Unpacked decimal numbers are stored as unsigned byte quantities. Onedigit is stored in each byte. The magnitude of the number is determined fromthe low-order half-byte; hexadecimal values 0-9 are valid and areinterpreted as decimal numbers. The high-order half-byte must be zero formultiplication and division; it may contain any value for addition andsubtraction.Packed BCD:A byte (packed) representation of two decimal digits, each in the range0 through 9. One digit is stored in each half-byte. The digit in thehigh-order half-byte is the most significant. Values 0-9 are valid in eachhalf-byte. The range of a packed decimal byte is 0-99.
It is not possible. A Byte is 8 bits, the largest possible 8 bit number is '11111111' which is only 255 (in normal decimal numbers).
There are 8 bits in a byte, so a two byte integer would be 16 bits. The largest 16 bit integer possible would be 11111111111111112, which is 65535 in base 10.
BCD (binary coded decimal) - 4 bit Byte - 8 bit Byte
2.0
The byte 00001000 represents the decimal number 8. In binary, each bit represents a power of 2, starting from the rightmost bit, which is 2^0. In this case, the byte has a '1' in the 2^3 position (8), and '0's in all other positions, resulting in the total value of 8.
One byte can represent a maximum of 256 different values, ranging from 0 to 255 in decimal notation. This is because a byte consists of 8 bits, and with each bit having two possible states (0 or 1), the total number of combinations is 2^8, which equals 256.