The maximum number of intersection points formed by 4 lines occurs when no two lines are parallel and no three lines are concurrent (i.e., they do not all meet at a single point). In this case, each pair of lines can intersect at a unique point. The number of ways to choose 2 lines from 4 is given by the combination formula ( \binom{n}{2} ), so for 4 lines, the maximum number of intersection points is ( \binom{4}{2} = 6 ).
When two circles intersect, they can create a maximum of 2 intersection points. Each straight line can intersect with each of the two circles at a maximum of 2 points, contributing 10 points from the lines and circles. Additionally, the five straight lines can intersect each other, yielding a maximum of ( \binom{5}{2} = 10 ) intersection points. Therefore, the total maximum points of intersection are ( 2 + 10 + 10 = 22 ).
Two distinct lines can intersect at most at one point. If the lines are not parallel, they will cross at a single point. If they are parallel, they will never intersect. Therefore, the maximum number of intersection points for two distinct lines is one.
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Five intersecting lines can have a maximum of 10 points of intersection, assuming that no two lines are parallel and no three lines intersect at the same point. Each pair of lines can intersect at one unique point, and the number of ways to choose 2 lines from 5 is given by the combination formula ( \binom{5}{2} = 10 ). Therefore, with optimal conditions, the maximum number of intersection points is 10.
Zero; parallel lines never intersect.
When two circles intersect, they can create a maximum of 2 intersection points. Each straight line can intersect with each of the two circles at a maximum of 2 points, contributing 10 points from the lines and circles. Additionally, the five straight lines can intersect each other, yielding a maximum of ( \binom{5}{2} = 10 ) intersection points. Therefore, the total maximum points of intersection are ( 2 + 10 + 10 = 22 ).
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Five intersecting lines can have a maximum of 10 points of intersection, assuming that no two lines are parallel and no three lines intersect at the same point. Each pair of lines can intersect at one unique point, and the number of ways to choose 2 lines from 5 is given by the combination formula ( \binom{5}{2} = 10 ). Therefore, with optimal conditions, the maximum number of intersection points is 10.
Zero; parallel lines never intersect.
false
thre lines that intersect in three points
infinety
A triangle? Three lines that intersect in three points.
The greatest number of intersection points that four coplanar lines can have occurs when no two lines are parallel and no three lines intersect at the same point. In this case, the maximum number of intersection points can be calculated using the formula ( \frac{n(n-1)}{2} ), where ( n ) is the number of lines. For four lines, this results in ( \frac{4(4-1)}{2} = 6 ) intersection points.
Parallel lines NEVER touch, so zero.
If it's a line it would only be 1, but if it's a parabola, or something with a curve, it could be multiple times.
depends on the position of the points if points are collinear, we have just only one line, the minimum number. If points are in different position (if any of the two points are not collinear) we have 21 lines (7C2), the maximum number of lines.