When two circles intersect, they can create a maximum of 2 intersection points. Each straight line can intersect with each of the two circles at a maximum of 2 points, contributing 10 points from the lines and circles. Additionally, the five straight lines can intersect each other, yielding a maximum of ( \binom{5}{2} = 10 ) intersection points. Therefore, the total maximum points of intersection are ( 2 + 10 + 10 = 22 ).
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69
The maximum number of intersection points formed by 4 lines occurs when no two lines are parallel and no three lines are concurrent (i.e., they do not all meet at a single point). In this case, each pair of lines can intersect at a unique point. The number of ways to choose 2 lines from 4 is given by the combination formula ( \binom{n}{2} ), so for 4 lines, the maximum number of intersection points is ( \binom{4}{2} = 6 ).
Five intersecting lines can have a maximum of 10 points of intersection, assuming that no two lines are parallel and no three lines intersect at the same point. Each pair of lines can intersect at one unique point, and the number of ways to choose 2 lines from 5 is given by the combination formula ( \binom{5}{2} = 10 ). Therefore, with optimal conditions, the maximum number of intersection points is 10.
Since there is no requirement for the line to be straight, the answer is infinitely many. Otherwise, 4.
32
No two circles can intersect more than twice. Each circle can intersect with each other circle. Thus there ought to be 2 × 30 × (30 - 1) intersections. However, this counts each intersection twice: once for each circle. Thus the answer is half this, giving: maximum_number_of_intersections = ½ × 2 × 30 × (30 - 1) = 30 × 29 = 870.
69
In three-dimensional space, two planes can either:* not intersect at all, * intersect in a line, * or they can be the same plane; in this case, the intersection is an entire plane.
discuss the possible number of points of interscetion of two distinct circle
6 maximum points of intersection
Since there is no requirement for the line to be straight, the answer is infinitely many. Otherwise, 4.
The greatest number of intersection points that four coplanar lines can have occurs when no two lines are parallel and no three lines intersect at the same point. In this case, the maximum number of intersection points can be calculated using the formula ( \frac{n(n-1)}{2} ), where ( n ) is the number of lines. For four lines, this results in ( \frac{4(4-1)}{2} = 6 ) intersection points.
15 mph
Minimum and maximum requirements: three straight lines meeting pairwise. Minimum and maximum requirements: three straight lines meeting pairwise. Minimum and maximum requirements: three straight lines meeting pairwise. Minimum and maximum requirements: three straight lines meeting pairwise.
Six (6)
of average product.