The maximum value of X minus the minimum value of X is calculated by subtracting the minimum value from the maximum value. This difference represents the range of the values of X. If you have specific values for X, you can determine the maximum and minimum values and then compute this difference accordingly.
It has an absolute minimum at the point (2,3). It has no maximum but the ends of the graph both approach infinity.
If x is the unknown or variable in an equation it can have many possible maximum or minimum values
When the quadratic is written in the form: y = ax2 + bx + c then if a > 0 y has a minimum if a < 0 y has a maximum and if a = 0 y is not a quadratic but y = bx + c, and it is linear. The maximum or minimum is at x = -b/(2a)
To determine the minimum or maximum of a parabola, you can use its vertex form, (y = a(x - h)^2 + k), where ((h, k)) is the vertex. If the coefficient (a) is positive, the parabola opens upwards and the vertex represents the minimum point; if (a) is negative, it opens downwards and the vertex represents the maximum point. You can also find the vertex using the formula (x = -\frac{b}{2a}) for a quadratic in standard form (y = ax^2 + bx + c). The corresponding (y)-value at this (x) gives you the minimum or maximum value.
A maximum!A maximum!A maximum!A maximum!
Assuming the standard x and y axes, the range is the maximum value of y minus minimum value of y; and the domain is the maximum value of x minus minimum value of x.
It has an absolute minimum at the point (2,3). It has no maximum but the ends of the graph both approach infinity.
The maximum value of the sine function, (\sin(x)), is 1, while the minimum value of the cosine function, (\cos(x)), is -1. Therefore, the sum of the maximum value of sine and the minimum value of cosine is (1 + (-1) = 0).
Both the function "cos x" and the function "sin x" have a maximum value of 1, and a minimum value of -1.
Sin(x) has a maximum value of +1 and a minimum value of -1.
If x is the unknown or variable in an equation it can have many possible maximum or minimum values
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In theory you can go down the differentiation route but because it is a quadratic, there is a simpler solution. The general form of a quadratic equation is y = ax2 + bx + c If a > 0 then the quadratic has a minimum If a < 0 then the quadratic has a maximum [and if a = 0 it is not a quadratic!] The maximum or minimum is attained when x = -b/2a and you evaluate y = ax2 + bx + c at this value of x to find the maximum or minimum value of the quadratic.
You cannot. The function f(x) = x2 + 1 has no real zeros. But it does have a minimum.
When the quadratic is written in the form: y = ax2 + bx + c then if a > 0 y has a minimum if a < 0 y has a maximum and if a = 0 y is not a quadratic but y = bx + c, and it is linear. The maximum or minimum is at x = -b/(2a)
(x-2) is not a factor of the numerator and so y tends to minus infinity as x approaches 2 from below. As x approaches 2 from above, y tends to plus infinity. There are, therefore, no maximum or minimum values for y.
The vertex of a parabola is the minimum or maximum value of the parabola. To find the maximum/minimum of a parabola complete the square: x² + 4x + 5 = x² + 4x + 4 - 4 + 5 = (x² + 4x + 4) + (-4 + 5) = (x + 2)² + 1 As (x + 2)² is greater than or equal to 0, the minimum value (vertex) occurs when this is zero, ie (x + 2)² = 0 → x + 2 = 0 → x = -2 As (x + 2)² = 0, the minimum value is 0 + 1 = 1. Thus the vertex of the parabola is at (-2, 1).