3.5
* * * * *
The mean deviation of ANY set of numbers must always be zero.
Easy. The mean deviation about the mean, for any distribution, MUST be 0.
standard normal
It is any standardised distribution.
T-scores have a mean of 50 and a standard deviation of 10. These values are fixed and do not change regardless of the distribution of T-scores.
Step 1: Find the mean Step 2: Find the deviation from the mean Step 3: Take the absolute value of the deviation Step 4: Find the mean of the absolute deviation. x----x-mean 63 63-63 0 69 69-63 6 62 62-63 -1 57 57-63 -6 64 64-63 1 mean = (63+69+62+57+64)/5 = 63 Taking the absolute deviations, we have 0,6,1,6,1 Averaging these deviations : (0+6+1+6+1)/5 =14/5 = 2.8 Mean absolute deviation = 2.8
Mean 0, standard deviation 1.
Mean = 0 Standard Deviation = 1
Easy. The mean deviation about the mean, for any distribution, MUST be 0.
No.
standard normal
It is any standardised distribution.
Standard deviation doesn't have to be between 0 and 1.
a is true.
T-scores have a mean of 50 and a standard deviation of 10. These values are fixed and do not change regardless of the distribution of T-scores.
z=(x-mu)/s = (-10+9)/2 z = -1/2 Note that the standard normal has a mean of 0, therefore: The value of -10 is to the left of the mean of -9 The value of -1/2 is to the left of the mean of 0.
T scores are also standardized norm scores, where the mean value is 50 and standard deviation value is 10, in contrast to Z scores where mean value is "0" and standard deviation value is 1. -Rama Reddy Karri
It is 7.062